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MaRussiya
1 month ago
10

An end of a light wire rod is bent into a hoop of radius r. The straight part of the rod has length l; a ball of mass M is attac

hed to the other end of the rod. The pendulum thus formed is hung by the hoop onto a revolving shaft. The coefficient of friction between the shaft and the hoop is µ. Find the equilibrium angle between the rod and the vertical.
Physics
1 answer:
ValentinkaMS [3.4K]1 month ago
8 0

Answer:

arcsin(\frac{R\mu}{(R+l)\sqrt{\mu^2+1}})

Explanation:

By applying the Law of Sines,

sin \theta = \frac{sin \phi R}{ l + R}

Based on Newton's Law,

mg = N\sqrt{\mu^2+1}

And the final equation also derived from Newton's Law,

\mu N = mgsin\phi

Then by consolidating all the equations together,

\mu N = mgsin\phi = N\sqrt{\mu^2+1}sin\phi\\

sin\theta = \frac{\mu R}{ (l + R)\sqrt{\mu^2+1}}

Thus,

\theta = arcsin(\frac{R\mu}{(R+l)\sqrt{\mu^2+1}})

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A 9.0-V battery moves 20 mC of charge through a circuit running from its positive terminal to its negative terminal. How much en
Yuliya22 [3333]

Answer:

The energy delivered is E = 0.18 J

Explanation:

Given,

Battery voltage, V = 9 V

Charge in the circuit, Q = 20 mC

                                        = 20 x 10³ C

Energy supplied in the circuit can be computed as

E = Q V

E = 20 x 10⁻³ x 9

E =  180 x 10⁻³

E equals 0.18 J.

The energy delivered in the circuit is therefore E = 0.18 J

7 0
1 month ago
Consider a perfectly insulated cup (no
ValentinkaMS [3465]

Answer:

When ice is subjected to heat, it melts; however, the temperature remains constant at 0◦ C.

Explanation:

Solution

The heat supplied by the heater is solely utilized for the melting of the ice, thus maintaining the temperature at 0◦ C.

Once all the ice has liquefied, the temperature of the resulting water will start to rise over time.

Note: please see the attached document with solutions featuring diagrams related to this explanation

7 0
2 months ago
4. We have 4 identical strain gauges of the same initial resistance (R) and the same gauge factor (GF). They will be used as R1,
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3 0
2 months ago
In a novel from 1866 the author describes a spaceship that is blasted out of a cannon with a speed of about 11.000 m/s. The spac
Sav [3153]

Answer:

a=0.284\ m/s^2

Explanation:

We start with the fact that

Initially, the spacecraft was at rest, u = 0

The final velocity of the rocket is given as v = 11 m/s

The distance that the rocket covers during acceleration is given as d = 213 m

We seek to determine the acceleration that the occupants of the spacecraft experience during launch, which is derived from the principles of kinematics. By applying the

third motion equation we can find the acceleration.

v^2-u^2=2ad\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(11)^2-(0)^2}{2\times 213}\\\\a=0.284\ m/s^2

Thus, the acceleration felt by those inside the spacecraft is 0.284\ m/s^2.

5 0
1 month ago
Two charges of 15 pC and −40 pC are inside a cube with sides that are of 0.40-m length. Determine the net electric flux through
Keith_Richards [3271]

To address this issue, we will utilize the principles related to Gauss' law, which states that the electric flux across a surface corresponds to the object's charge divided by the permittivity of vacuum. In mathematical terms, this can be expressed as

\phi = \frac{Q_{net}}{\epsilon_0}

It's crucial to remember that the net charge equals the difference between the two specified charges, so upon substitution,

\phi = \frac{(15-40)*10^{-12}C}{8.85*10^{-12}C^2/Nm^2}

\phi = 2.82WB

The negative sign indicates that the flux is directed into the surface

4 0
2 months ago
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