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4 days ago

Why did the acorn fall to earth instead of rising up to the moon?

Physics

2 answers:

Maru [3.2K]4 days ago

8 0

The acorn fell to the ground rather than ascending to the moon due to the greater gravitational pull of the Earth.

ValentinkaMS [3.3K]4 days ago

4 0

Gravitational forces act upon any two masses, with the strength dependent on the mass of each body and inversely proportional to the distance separating them. As distance increases, the gravitational influence diminishes. The acorn descends toward Earth for two primary reasons: 1. Earth’s mass is greater than that of the Moon; 2. The acorn is situated closer to Earth. Hence, the force of gravity drawing it towards Earth is stronger.

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A large box of mass m sits on a horizontal floor. You attach a lightweight rope to this box, hold the rope at an angle θ above t

inna [2995]

Answer:

The answer to the specified question will be " $\mu_{s}=\frac{T_{m}Cos\theta}{M_{g}-T_{m}Sin\theta}$ ".

Explanation:

Referring to the question,

$\sum F_{x}$

⇒ $TCos \theta-F_{s}=0$

⇒ $T_{m}Cos \theta =F_{s}$ ...(equation 1)

$\sum F_{y}$

⇒ $TSin \theta+F_{N}=m_{g}$

⇒ $M_{g}-TSin \theta=F_{N}$ ...(equation 2)

Now,

From equation 1 and equation 2, we conclude

⇒ $T_{m} Cos \theta = \mu_{s}F_{N}$

By substituting the value of $F_{N}$ , we derive

⇒ $T_{m} Cos\theta = \mu_{s}(M_{g}-T_{m}Sin \theta)$

⇒ $\mu_{s}=\frac{T_{m}Cos\theta}{M_{g}-T_{m}Sin\theta}$

4 0

1 month ago

A kangaroo jumps to a vertical height of 2.8 m. How long was it in the air before returning to earth

serg [3469]

The kangaroo reaches a maximum vertical altitude of 2.8 m, which can be calculated using the formula 2.8 = 1/2 * 9.8 * t^2. Thus, applying the equation s = ut + 1/2at^2.

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1 month ago

Quando aquecemos água em nossas casas, ao nível do mar, utilizando um recipiente aberto, sua temperatura nunca ultrapassa os 100

Softa [2943]

Answer:

I do not communicate in Spanish

Explanation:

4 0

18 days ago

d. The force is doubled and the object’s mass is halved? 18. ||| A man pulling an empty wagon causes it to accelerate at 1.4 m/s

Yuliya22 [3228]

Assuming that the mass of the empty wagon is "M," according to Newton's second law, we can derive the following relationships. Given that the empty wagon accelerates at 1.4 m/s², we proceed with this information. If a child weighing three times the mass of the wagon is on it, we can establish the relevant equations.

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23 days ago

Which of the following combinations of variables results in the greatest period for a pendulum? length = L, mass = M, and maximu

Yuliya22 [3228]

Response:

length = 2L, mass = M/2, and maximum angular displacement = 1 degree

Clarification:

We examine only small amplitude oscillations (as in this scenario), which keeps the angle θ sufficiently small. In such situations, it's important to note that the pendulum's motion can be described by the equation:

$\ddot{\theta}=\frac{g}{l}\theta$

The resulting solution is:

$\theta=Asin(\omega t + \phi)$

Here, $\omega=\sqrt\frac{g}{l}$ represents the angular frequency of the oscillations, enabling us to find the period:

$T=\frac{2\pi}{\omega}\\T=2\pi\sqrt\frac{l}{g}$

As a result, the period of a pendulum is determined solely by its length and is independent of both its mass and angle, provided the angle remains small. Therefore, the choice with the longest length gives the longest period.

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8 days ago