A flask of fixed volume contains 1.0 mole of gaseous carbon dioxide and 88 g of solid carbon dioxide. The original pressure and

Explanation:

Elements provided:

  F, Sr, P, Ca, O, Br, Rb, Sb, Li, S

Elements sharing similar reactivity belong to the same group in the periodic table, indicating that those in the same column exhibit comparable reactivity. Here are the identified groupings:

  Li and Rb are alkali metals in group 1

  Ca and Sr are alkaline earth metals in group 2

  F and Br are halogens in group 7

  O and S belong to group 6

 P and Sb are classified in group 5 of the periodic table

Thus, these classifications illustrate elements with the same chemical characteristics.

Answer:

The temperature difference is 293.15 Kelvin.

Explanation:

The provided information:

The temperature difference between the two matters is 20°C

We need to determine this difference in Kelvin =?

To solve this;

Using the formula:

0°C +273.15

Now substituting the values in place of 0.

20°C + 273.15 = 293.15 K

Hence, the temperature differential between the two samples is 293.15 K.

Answer:

The molality is 1.15 m.

Molality is calculated by dividing the number of moles of solute by the kilograms of solvent, which in this case is water.

Calculate moles of H₂SO₄ from molarity:

C = n/V → n = C × V = 6.00 mol/L × 0.048 L = 0.288 moles

Mass of solvent (water) based on density:

m = ρ × V = 1.00 kg/L × 0.250 L = 0.250 kg

Therefore, molality is:

m = moles/solvent mass = 0.288 moles / 0.250 kg = 1.15 m

Answer:

Wood

Explanation: