Explanation:
The formula illustrating the relationship between resistance and temperature is as follows:
R =
![R_{o} + \alpha [T_{2} - T_{1}]](https://tex.z-dn.net/?f=R_%7Bo%7D%20%2B%20%5Calpha%20%5BT_%7B2%7D%20-%20T_%7B1%7D%5D)
where, R = final resistance
= initial resistance
= temperature coefficient of resistivity
= final temperature 
= initial temperature
Given data as follows.
R = 36 ohm,
= 3 ohm
= 0.0045
Substituting the provided values into the above formula gives us the following.
R =
36 =
=
![3 + 0.0045 \times [T_{2} - 293]](https://tex.z-dn.net/?f=3%20%2B%200.0045%20%5Ctimes%20%5BT_%7B2%7D%20-%20293%5D)
= 7626.33 K
Thus, it can be concluded that 
the temperature of the light bulb at 12.0 V is 7626.33 K.
Response:
2.5kN.m
Details:
Torque relates directly to the pitch diameter
= Ta/Tb= Da/Db
For 120/Tb= 0.25/0.5
This gives Tb= 2.469kN.m, roughly 2.5kN.m
To respond to the previous question:
<span>Q = heat quantity (kJ) </span>
<span>cp = specific heat (kJ/kg.K) = 4.187 kJ/kgK </span>
<span>m = weight (kg) </span>
<span>dT = temperature change between hot and cold water (K). Note: dt in °C is identical to dt in Kelvin </span>
<span>Q = 100kg * (4.187 kJ/kgK) * 15 K </span>
<span>Q = 6,280.5 KJ = 6,280,500 J = 1,501,075.5 cal</span>
Answer:
Unfortunately, I do not possess the information
Explanation:
