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schepotkina
14 days ago
5

A frictionless inclined plane is 8.0 m long and rests on a wall that is 2.0 m high. How much force is needed to push a block of

ice weighing 300.0 N up the plane

Physics
1 answer:
serg [3.5K]14 days ago
7 0

Provided Information:

Length of inclined plane = 8 m

Height of inclined plane = 2 m

Weight of the ice block = 300 N

Required Information:

Force needed to push ice block = F =?

Answer:

Force needed to push the ice block = 75 N

Explanation:

The required force to push this ice block up an inclined plane is given by

F = Wsinθ

where W is the weight of the ice block and θ is the angle indicated in the attached image.

Using trigonometric ratios,

sinθ = opposite/hypotenuse

where the opposite side is the height of the inclined plane and the hypotenuse is the length of the inclined plane.

Thus, sinθ = 2/8

θ = sin⁻¹(2/8)

which leads to θ = 14.48°

Therefore, F = 300*sin(14.48)

results in F = 75 N

This indicates that a force of 75 N is necessary to push the ice block on the specified inclined plane.

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