To solve this problem, it's crucial to convert all measurements to the same units.
We first need to convert 80 minutes into hours.
So:
80 minutes × (1 hour ÷ 60 minutes) = 1.3333 hours.
The flow rate we have is Q = 150 liters per hour.
To determine how many liters of water are released, we perform the following calculation:
150 liters/hour × 1.333 hours = 200 liters.
In conclusion, 200 liters of water will be released in 80 minutes.
a.) 10 Hz b.) 0.1 s c.) 187.4 m/s d.) -412.6 m/s²
Answer:
W = -510.98 J
Explanation:
Force = 43 N, 61° SW
Displacement = 12 m, 22° NE
The work done is calculated using:
W = F*d*cos(A)
where A is the angle between the applied force and displacement.
The angle A between the force and displacement is determined as A = 61 + 90 + 22 = 172°
Hence, W = 43 * 12 * cos(172)
This results in W = -510.98 J
The negative result indicates that the work is done contrary to the direction of the force applied.
When helium is released from a compressed container, the decompressed atoms expand and rise, causing the rubber balloon to inflate and float along. In this scenario, helium exists in a gaseous state.
Answer:

Explanation:
The stone reaches the top of the flagpole at both t = 0.5 s and t = 4.1 s
therefore, the total duration of the upwards motion above the peak of the pole is provided as

now we have



this indicates the speed at the flagpole's top
at this point we have



the height of the flagpole is stated as


