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kakasveta
1 month ago
10

A transition metal complex in solution has an absorption peak at 450 nm, in the blue region of the visible spectrum. What color

is this solution?
A) Violet B) Orange C) Green D) Blue

Physics
1 answer:
Maru [3.3K]1 month ago
7 0

Response:

For a transition metal complex in solution exhibiting an absorption peak at 450 nm, which falls within the blue section of the visible spectrum, the corresponding (complementary) color of this solution is orange (option B).

Rationale:

The amount of UV-visible light absorbed indicates that some electromagnetic radiation successfully passes through the sample and is perceivable by the human eye. Thus, the color apparent in the visible spectrum of a complex aligns with the wavelengths of light it allows to pass rather than those it absorbs. The color that is absorbed will be complementary to the one that is transmitted.

In the accompanying image, you can view the associated wavelengths alongside their respective colors. By identifying the wavelength associated with the absorbed color, you will be able to see the complementary color that is visible or reflected.

For a transition metal complex in solution exhibiting an absorption peak at 450 nm, which falls within the blue section of the visible spectrum, the corresponding (complementary) color of this solution is orange (option B).

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1) The wave's period remains constant across different media

2) The wave's velocity varies depending on the medium it travels through

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Clarification:

1)

The period of a wave signifies the duration it takes for one full oscillation.

The wave's period is the inverse of its frequency:

T=\frac{1}{f}

where

T denotes the period

f is the frequency

The provided table illustrates that the frequency remains consistent across the three media; hence, the period is unchanged as it solely relies on frequency. We can compute it as we know that

f = 350 Hz

thus the period equals

T=\frac{1}{350}=2.86\cdot 10^{-3} s = 2.86 ms

2)

The velocity of a wave can be derived from the wave equation:

v=f \lambda

where

f indicates the frequency

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<pin the="" first="" medium="">

f=350 Hz, \lambda = 0.75 m, resulting in a speed of

v_1 = (350)(0.75)=262.5 m/s

In the second medium,

f=350 Hz, \lambda = 0.70 m, leading to a speed of

v_2 = (350)(0.70)=245 m/s

In the third medium,

f=350 Hz, \lambda = 0.65 m, showing a speed of

v_3 = (350)(0.65)=227.5 m/s

As a result, we conclude that the wave's speed varies with the medium.

3)

<pwhen a="" wave="" shifts="" from="" one="" medium="" to="" another="" the="" following="" occurs:="">

- The wave's direction alters. Specifically, if the subsequent medium is of greater optical density, the wave bends towards the normal; conversely, it bends away if the second medium is of lesser optical density.

- The wave's speed is affected. The wave decelerates in media with higher optical density and accelerates in those with lower optical density.

- The wave's frequency remains unchanged.

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