(a) Calculate the absolute pressure at the bottom of a fresh- water lake at a depth of 27.5 m. Assume the density of the water i

Question

3 months ago

8

(a) Calculate the absolute pressure at the bottom of a fresh- water lake at a depth of 27.5 m. Assume the density of the water i

s 1.00 3 103 kg/m3 and the air above is at a pressure of 101.3 kPa. (b) What force is exerted by the water on the window of an underwater vehicle at this depth if the window is circular and has a diameter of 35.0 cm?

Physics

2 answers:

Maru [3.3K] · Answer 1 · 2026-03-18T05:56:50+03:00

Maru [3.3K]3 months ago

6 0

Response:

(a) The absolute pressure is calculated to be 371.6 kPa

(b) The force that the water exerts is 26.0 kN

Clarification: Please refer to the attachments below

kicyunya [3.2K] · Answer 2 · 2026-03-18T05:57:27+03:00

kicyunya [3.2K]3 months ago

5 0

Response:

a) $P = 370.993\,kPa$ , b) $F = 25.948\,kN$

Clarification:

a) The absolute pressure at a depth of 27.5 meters is:

$P = P_{atm} + P_{man}$

$P = 101.3\,kPa + \left(1000\,\frac{kg}{m^{3}}\right)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (27.5\,m)\cdot \left(\frac{1\,kPa}{1000\,Pa} \right)$

$P = 370.993\,kPa$

b) The force applied by the water is:

$F = (P - P_{atm})\cdot A$

$F = (370.993\,kPa-101.3\,kPa)\cdot \left(\frac{\pi}{4} \right)\cdot (0.35\,m)^{2}$

$F = 25.948\,kN$