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Semenov
12 days ago
7

A store owner is interested in opening a second shop. She wants to estimate the true average daily revenue of her current shop t

o decide whether expanding her business is a good idea. The store owner takes a random sample of 60 days over a six-month period and finds that the mean revenue of those days is 3,472.00 dollars with variance 315,900.20 square dollars. Calculate a 95% confidence interval to estimate the true average daily revenue.
Mathematics
1 answer:
babunello [3.6K]12 days ago
6 0
Every confidence interval correlates with a specific z value. As the confidence interval expands, so does the corresponding z value.
You can compute the confidence interval using the formula:
\overline{x} \pm \frac{zs}{\sqrt n}
Here \overline{x} represents the mean, z is the respective z value, s denotes the standard deviation, and n indicates the sample size.
Standard deviation is simply the square root of variance:
s=\sqrt{315900.20}=\$562.05
For a confidence interval of 95%, the z value is <span>1.960.
</span>Now, we can compute the confidence interval for our income:
3472.00\pm \frac{1.960\cdot 562.05}{\sqrt{60}}\\ \$3472.00\pm142.22


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Thus, Uc(t) = Pcos wt  + Qsin wt = 8 cos wt /(1- w^2).

Combining gives us U(t) = uh(t ) + Uc(t)

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U(0) = C1cos(0) + c2 sin (0) + 8 cos (0) /(1- w^2)

Which leads us to C1 + 8 /(1- w^2) = 5

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