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Lesechka
9 days ago
8

A principal is ordering new books. The number of books she order is 25 times the number of classes plus 8. Represent the relatio

nship between the number of books ordered and the number of classes in the table below. Number of classes:1, 2, 3, 4, 5. Books:?
How many books does the principal need to order for 10 classes?
If the principal orders 233 books, how many classes are there
Mathematics
1 answer:
Leona [12.6K]9 days ago
6 0
1 = 25 times 1 + 8 = 33 2 = 25 times 2 + 8 = 58 3 = 25 times 3 + 8 = 83 4 = 25 times 4 + 8 = 108 5 = 25 times 5 + 8 = 133 B 10 = 25 times 10 + 8 = 258 C 233 = 25 times x + 8 233 = 25x + 8 233 - 8 = 25x 225 = 25x 225 / 25 = 25x / 25 9 = x there are 9 classes.
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Find the distance from (4, −7, 6) to each of the following.
Zina [12379]

Answer:

(a) 6 units

(b) 4 units

(c) 7 units

(d) 9.22 units

(e) 7.21 units

(f) 8.06 units

Step-by-step explanation:

The distance between two points, (x₁, y₁, z₁) and (x₂, y₂, z₂), can be calculated using;

d = √[(x₂ - x₁)² + (y₂ - y₁)² + (z₂ - z₁)²]

According to the problem;

(a) The distance from (4, -7, 6) to the xy-plane

The xy-plane corresponds to where z equals 0, so

xy-plane = (4, -7, 0).

Thus, the distance d is calculated from (4, -7, 6) to (4, -7, 0)

d = √[(4 - 4)² + (-7 - (-7))² + (0 - 6)²]

d = √[(0)² + (0)² + (-6)²]

d = √(-6)²

d = √36

d = 6

Thus, the distance to the xy-plane is 6 units

(b) The distance from (4, -7, 6) to the yz-plane

The yz-plane is located where x is 0, hence

yz-plane = (0, -7, 6).

So, the distance d is from (4, -7, 6) to (0, -7, 6)

d = √[(4 - 0)² + (-7 - (-7))² + (6 - 6)²]

d = √[(4)² + (0)² + (0)²]

d = √(4)²

d = √16

d = 4

Thus, the distance to the yz-plane is 4 units

(c) The distance from (4, -7, 6) to the xz-plane

The xz-plane exists where y is 0, meaning

xz-plane = (4, 0, 6).

The distance d from (4, -7, 6) to (4, 0, 6)

d = √[(4 - 4)² + (-7 - 0)² + (6 - 6)²]

d = √[(0)² + (-7)² + (0)²]

d = √[(-7)²]

d = √49

d = 7

Thus, the distance to the xz-plane is 7 units

(d) The distance from (4, -7, 6) to the x-axis

The x-axis is defined by y and z being 0, which implies

x-axis = (4, 0, 0).

Thus, the distance d is from (4, -7, 6) to (4, 0, 0)

d = √[(4 - 4)² + (-7 - 0)² + (6 - 0)²]

d = √[(0)² + (-7)² + (6)²]

d = √[(-7)² + (6)²]

d = √[(49 + 36)]

d = √(85)

d = 9.22

Hence, the distance to the x-axis is 9.22 units

(e) The distance from (4, -7, 6) to the y-axis

The y-axis is defined where x and z are both 0, thus

y-axis = (0, -7, 0).

Thus, the distance d is from (4, -7, 6) to (0, -7, 0)

d = √[(4 - 0)² + (-7 - (-7))² + (6 - 0)²]

d = √[(4)² + (0)² + (6)²]

d = √[(4)² + (6)²]

d = √[(16 + 36)]

d = √(52)

d = 7.22

Thus, the distance to the y-axis is 7.21 units

(f) The distance from (4, -7, 6) to the z-axis

The z-axis is defined by x and y being 0, which gives

z-axis = (0, 0, 6).

Thus, the distance d is calculated from (4, -7, 6) to (0, 0, 6)

d = √[(4 - 0)² + (-7 - 0)² + (6 - 6)²]

d = √[(4)² + (-7)² + (0)²]

d = √[(4)² + (-7)²]

d = √[(16 + 49)]

d = √(65)

d = 8.06

Thus, the distance to the z-axis is 8.06 units

5 0
1 month ago
How to round 47,125 to the nearest ten,to the nearest hundred, to the nearest thousand and to the nearest ten thousand
zzz [12365]
To round the figure 47,125 to the closest tenth, hundredth, and thousandth, it's essential to recognize the positions of these places. The tens position is the second digit from the right. The hundreds position is the third, and the thousands position is the digit immediately following the comma. For rounding to the tens place, you must inspect the digit directly behind it (the ones place) and evaluate. If this digit is between 0-4, you won’t round the tens place, but if it falls between 5-9, rounding is permissible. The same regulation applies when rounding up for the hundreds and thousands places. Consequently, the number arrived at is - 47,135. 
8 0
1 month ago
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76% is between which of the following two numbers?
AnnZ [12381]

Hi there!

While there are no answer choices provided, here's how you can solve a problem like this.

To find the average of two numbers, you simply sum them up and divide by two!

For instance, to find the midpoint between 1 and 3, you add 1 and 3 to get 4, then divide by 2 which results in 2!

For 100 and 580, adding gives you 680, and dividing by 2 results in 340!

The average between 0.57 and 0.69 involves adding to get 1.26, then dividing by 2 yields 0.63!

Now, with percentages, for 45% and 67%, the addition gives you 112%, and dividing that by 2 will result in 56%!

So, for your answer options, just calculate the total and divide by two to determine which one results in 76%!

I hope this information helps!

5 0
1 month ago
Delaney would like to make a 10 lb nut mixture that is 60% peanuts and and 40% almonds. She has several pounds of peanuts and se
AnnZ [12381]

Response:

If there are "p" pounds of peanuts and "m" pounds of a mixture containing '20% peanuts and 80% almonds', then we can formulate the following equations:

p + m = 10 -----------(1) and

4m/5 = 4 ------------(2)

The solution yields 5 lb peanuts and 5 lb mixture.

Detailed explanation:

In the mixture that Delaney desires to create, there will be

\frac {10 \times 60}{100} lb

= 6 lb of peanuts

Thus, there will be (10 - 6) lb

= 4 lb of almonds

If Delaney has "p" pounds of peanuts and "m" pounds of the '20% peanuts and 80% almonds' mixture, then based on the problem statement,

p + m = 10 -----------(1) and

4m/5 = 4 ------------(2)

From equation (2), we derive

m = 5 --------------(3)

From (1) and (3), we find that

p = (10 - 5) = 5

7 0
12 days ago
You can upgrade lighting at your factory to LED bulbs that cost $6.95 each and last an average of 5 years. It costs $3 in labor
Inessa [12570]
Each LED bulb, along with installation labor, is priced at
.. $6.95 +$3 = $9.95

For 100 bulbs over a span of 10 years, that equals (100*10) = 1000 bulb·years. At $9.95 per bulb, 5 bulb·years are obtained, and thus the projected total cost for 1000 bulb·years is
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In summary, for a decade, the installation and changes of 200 bulbs in 100 lamps amount to $1990. Therefore, the yearly cost is...
.. $1990/(10 yr) = $199/yr
3 0
1 month ago
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