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Stells
1 month ago
5

What do you think life on earth would be like if chemistry had not been put to practical use?​

Chemistry
1 answer:
KiRa [2.9K]1 month ago
5 0

Answer:

If practical applications for chemistry hadn't been explored, our understanding of what it means to be human, and the biological aspects that make us who we are, would remain unclear. Moreover, we wouldn't have achieved significant advancements in areas such as vaccines and other critical fields.

Explanation:

You might be interested in
Combustion analysis of an unknown compound containing only carbon and hydrogen produced 0.2845 g of co2 and 0.1451 g of h2o. wha
VMariaS [2998]
CxHy + (x+0.25)O₂ → xCO₂ + 0.5yH₂O

m(CO₂)/{xM(CO₂)}=m(H₂O)/{0.5yM(H₂O)}

0.2845/{44.01x}=0.1451/{9.01y}

x/y=0.4=2:5

The empirical formula is C₂H₅.
7 0
1 month ago
A 0.100 m solution of which one of the following solutes will have the highest vapor pressure? A 0.100 m solution of which one o
eduard [2782]
Vapor pressure refers to the force exerted by vapor or gas molecules above the surface of a liquid. It is inversely related to the concentration of solute particles; an increase in solute concentration results in a decrease in vapor pressure, and vice versa. For (a), it dissociates into two particles. In (b), the total count of particles from dissociation becomes 1 + 2, totaling three. For (c), dissociation yields 1 + 3 for a total of four particles. (d) Since sucrose is a covalent compound, it does not break apart into ions, so it remains as one particle. For (e), dissociation results in 1 + 1, equating to two particles.
5 0
17 days ago
Bleach contains the active ingredient NaClO. Analysis of bleach involves two sequential redox reactions: First, bleach is reacte
VMariaS [2998]

Answer:

0.31%

Explanation:

For the chemical reaction:

I₂ + 2 S₂O₃²⁻ → 2 I⁻ + S₄O₆²⁻

0.043 L multiplied by 0.117 M of sodium thiosulfate gives 5.031x10⁻³ moles of S₂O₃²⁻

5.031x10⁻³ moles of S₂O₃²⁻ produces:

ClO⁻⁻ + 2 H⁺ + 2 I⁻ → I₂ + Cl⁻ + H2O

2.5156x10⁻³ moles of I₂ equates to moles of NaClO

2.5156x10⁻³ moles of NaClO times \frac{74,44 g}{1mol} yields 0.187 g of NaClO

Thus, the mass percentage composition is:

\frac{0,187 g of NaClO}{60 g Of Bleach} x 100 = 0.31%

I hope this helps!

5 0
1 month ago
How to calculate electronegativity with 3 elements?
VMariaS [2998]
For instance, what is the difference in electronegativity for Acetone(CH2O)? Are there two distinct values, namely 0.4 for C versus H and 1.0 for C versus O? How do you decide which one to adopt?

6 Comments

AlwaysReady1

•

Apr 3, 2016, 10:14 PM

I may not fully grasp the question, but if you’re seeking to determine a compound's electronegativity to assess its electron-attracting capability, there are various other influencing factors.

It varies depending on the compound. For example, CH2O, known as formaldehyde, has oxygen with two pairs of electrons that can be donated. Neither hydrogen nor carbon can bond further as they are already fulfilling their valence shell requirements.

Robo94

•



You're attempting to apply a concept from a binary system to a more complex one. I assume you're aiming to figure out a molecule's dipole moment. In the case of a diatomic molecule (where A is bonded to B), the potential difference can simply be determined as A minus B. For larger molecules, the calculations become much more involved.

If this inquiry is related to homework assistance, it’s a distinctly different method from what you might be accustomed to. I recommend starting with water and then expanding out from there.

Check this out: https://www.khanacademy.org/science/organic-chemistry/gen-chem-review/electronegativity-polarity/v/dipole-moment

Philosoaxolotl

•



Electronegativity pertains to single elements (or rather individual atoms) and lacks straightforward applicability to broader molecules.

What precisely are you aiming to do with this data? If you're delving into how electrons transition between molecules, the situation is more intricate—within a molecule, the more electronegative elements pull electrons from other atoms (which frequently happens in organic compounds, such as when oxygen bonds with carbon and pulls in some of its electrons). Nevertheless, this effect diminishes in lengthened molecules. The system is more complicated as molecules do not possess a single, constant electronegativity (which is more accurate for atoms); instead, they exhibit varied localized charge regions that will respond differently.

From what I gather, your question pertains to the electronegativity difference among the atoms within an acetone molecule. This indeed relies on which two atoms you are examining and won't remain constant throughout; however, the difference won't simply match the values listed in an electronegativity table due to the factors discussed earlier.

This explanation might seem a bit hazy, and I’m just an undergraduate, so please take my interpretation lightly, but I am open to clarifying further if needed.

cheeseborito

•



That statement is inaccurate.

Electronegativity represents the attraction an atom holds for the electrons in a covalent bond with another atom. Essentially, an element does not have a singular electronegativity; it fluctuates based on its bonding partners. We cannot discuss the electronegativity of an atom in isolation.

While average values are useful for practical discussions (though they may not capture the nuance), the effective electronegativity of an oxygen atom bonded to carbon will remain fairly consistent.

As far as my understanding goes, even though my definition of electronegativity may lack precision, the influence an oxygen atom has on the electrons of a carbon atom is affected by what the carbon is bonded to. For instance, the local charge around the oxygen in acetic acid will be more pronounced than that in decanoic acid.

I may have phrased the electronegativity issue poorly—what I meant was the interaction between pairs of atoms as related to one another. An oxygen will exert a consistent pull regarding a carbon atom, but the changes in local charge can differ due to the influence of surrounding atoms, making the topics we typically utilize electronegativity to clarify substantially more intricate.
6 0
1 month ago
In a titration 5.0 mL of a 2.0 M NaOH aq solution exactly neutralizes 10.0 of an HCL aq solution what is the concentration of th
VMariaS [2998]
The concentration of the HCl solution can be determined as follows:

The reaction equation is written as

NaOH + HCl = NaCl + H2O

Next, the moles of NaOH are calculated: moles = molarity x volume /1000

= 5 x 2/1000 = 0.01 moles

Using the mole ratio of NaOH to HCl, which is 1:1, the moles of HCl is also equal to 0.01 moles

The concentration is given by: concentration = moles/volume x 1000

= 0.01/10 x 1000 = 1M

8 0
1 month ago
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