Answer:
Ir(NO2)3
Explanation:
The molar mass is 330.2335, in case that's also required.
Explanation:
Initial moles of ethanoic acid = 0.020 mol
At equilibrium, half of the ethanoic acid molecules have reacted.
Thus, moles of ethanoic acid reacted = 0.020 mol * (50% / 100%)
= 0.010 mol
Moles of ethanoic acid remaining = 0.020 mol - 0.010 mol = 0.010 mol
The moles of product
gas formed are determined as follows:
0.010 mol CH3COOH * (1 mol
/ 2 mol CH3COOH)
= 0.005 mol 
Consequently, the total moles of gas present in the vessel at equilibrium are 0.010 mol CH3COOH and 0.005 mol 
Total gas moles at equilibrium = 0.010 mol + 0.005 mol = 0.015 mol
Next, let’s determine the pressure:
0.020 mol of gas has a pressure of 0.74 atm; so under the same conditions, we find the pressure exerted by 0.015 mol of gas:
P1/n1 = P2/n2
P2 = P1*(n2 / n1)
= 0.74 atm * (0.015 mol / 0.020 mol)
= 0.555 atm
A. 1.01 is the accurate result
Because
The formula used is Pv= nRT
P=1 atm
V= 22.4 L
N= x
R= 0.0821
T= 273 K (since it’s standard temperature)
Thus, (1)(22.4)=(x)(0.0821)(273)
X= 1.001