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Illusion
15 days ago
6

Imagine you are a lab technician, and a colleague informs you there have been problems with the 25.0-mL samples you have been pr

oviding. You know you have been measuring the volume carefully and reading the meniscus correctly, so you decide to check the calibration of the graduated cylinder you have been using. You fill the graduated cylinder with water at 25 °C up to the 25.0 mL mark, and then measure the mass of this volume of water. You find that the mass is 22.4 g. The density of water at 25 °C is 0.99704 g/mL. What is the actual volume of the water?
Chemistry
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A flask that can hold 158 g of water at 4oc can hold only 127 g of ethanol at the same temperature. what is the density of ethan
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Answer:

  • The density of ethanol measures 0.80 g/ml.

Explanation:

The density of water is known to be 1 g/ml, indicating that 158 g of water occupies a volume of 158 ml.

            d = m/v = 258/258 = 1 g/ml

This implies the volume will remain the same for ethanol.

            hence, the density of ethanol = 127/158 = 0.80 g/ml

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Which statements describe how stars are born? Check all that apply. Stars are born in clouds of gas and dust called nebulas. The
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How quickly must non-frozen ready-to-eat foods be consumed?
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I think it should be 24 hours.

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3 months ago
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How many atoms are in 80.45 g of magnesium?
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Greetings!

To determine the number of atoms present in 80.45 grams of magnesium, we require Avogadro's number and the weight of a single mole of magnesium.

Avogadro's number is 6.02 x 10^23 atoms, and the mass of one mole of magnesium is 24.31 grams.

1. First, divide by the weight of one mole of magnesium

80.45 / 24.31 ≈ 3.309 moles (rounded to appropriate significant figures)

2. Multiply the number of moles by Avogadro's number

3.309 x (6.02 x 10^23) ≈ 1.99 x 10^24 (rounded to appropriate significant figures)

Thus, in 80.45 grams of magnesium, there are approximately 1.99 x 10^24 atoms.

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