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kvasek
4 days ago
11

A parallel-plate capacitor is constructed of two horizontal 12.0-cm-diameter circular plates. A 1.0 g plastic bead, with a charg

e of -6.0 nC, is suspended between the two plates by the force of the electric field between them.
Required:
a. Which plate, the upper or the lower, is positively charged?
b. What is the charges on positvie plate?
Physics
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Subsurface ocean currents continually circulate from the warm waters near the equator to the colder waters in other parts of the
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<span>The primary factor behind these currents is the </span>variability in the density of ocean waters.
8 0
1 month ago
Suppose a rectangular piece of aluminum has a length D, and its square cross section has the dimensions W XW, where D (W x W) to
kicyunya [3294]

Answer:

R₂ / R₁ = D / L

Explanation:

The resistance for a metal can be calculated by

        R = ρ L / A

Where ρ indicates the resistivity of aluminum, L is the resistance's length, and A indicates the cross-sectional area

We use this formula for both configurations

For small face measurements (W x W)

The length is

         L = W

Area  

         A = W W = W²

         R₁ = ρ W / W² = ρ / W

For larger face measurements (D x L)

       Length L = D= 2W

       Area     A = W L

     R₂ = ρ D / WL = ρ 2W / W L = 2 ρ/L

From this, we find the relation to be

    R₂ / R₁ = 2W²/L

6 0
2 months ago
The drawing shows three particles far away from any other objects and located on a straight line. The masses of these particles
Sav [3153]
The masses of particle A, B, and C are given, with all three particles aligned linearly. The distances between them are noted. The gravitational forces are attractive, compounding when acting in the same direction. The effects on each particle are formulated based on their distances.
3 0
2 months ago
A diver explores a shallow reef off the coast of Belize. She initially swims d1 = 74.8 m north, makes a turn to the east and con
inna [3103]

Response:R=1607556m

θ=180degrees

Clarification:

d1=74.8m

d2=160.7km=160.7km*1000

d2=160700m

d3=80m

d4=198.1m

Utilizing an analytical approach:

Rx=-(160700+75*cos(41.8))= -160755.9m

Ry= -(74.8+75sin(41.8))-198.1=73m

Magnitude, R:

R=√Rx+Ry

R=√160755.9^2+20^2=160755.916

R=160756m

Direction,θ:

θ=arctan(Rx/Ry)

θ=arctan(-73/160755.9)

θ=-7.9256*10^-6

It is worth noting that since θ is in the second quadrant, 180 is added

θ=180-7.9256*10^6=180degrees

8 0
1 month ago
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