0.183. This problem addresses Binomial Probability. The formula is nCx × p^x × q^(n - x), where p = 0.72 and q = 1 - p = 0.28. With x representing the number of successes equal to 9 and n being 10, we are calculating the probability that at least nine out of ten people utilized an online travel website for booking. At least 9 out of 10 translates to x ≥ 9, so we calculate P(x ≥ 9) for x = 9 and x = 10. This leads to: P(x ≥ 9) = 10C9 × (0.72^9 × 0.28^(10 - 9)) + 10C10 × (0.72^10 × 0.28^(10 - 10)), resulting in approximately P(x ≥ 9) = 0.183.
Beth travelled the remaining distance with an average speed of 52 mph
Solution:
Given, Beth drives 200 miles in 4 hours.
The equation for distance speed is expressed as:
--- eqn 1
Calculating time spent for 18 miles:
She completes the initial 18 miles at an average speed of 36 mph.
Distance here equals 18 miles
speed equals 36 mph
Substituting values into eqn 1 yields,

Determining average speed for the remaining journey:
The distance left to cover is = 200 miles – 18 miles = 182 miles
The time spent on the remaining trip equals the total time minus the duration for the first 18 miles

Inserting values into eqn 1 gives us

This confirms that the average speed for the rest of the journey is 52 mph