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Delicious77
15 days ago
3

Find the next number in the number sequence 4, 9, 16, 25

Mathematics
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Suppose that the probability that a person books an airline ticket using an online travel website is 0.72. Consider a sample of
Inessa [12570]
0.183. This problem addresses Binomial Probability. The formula is nCx × p^x × q^(n - x), where p = 0.72 and q = 1 - p = 0.28. With x representing the number of successes equal to 9 and n being 10, we are calculating the probability that at least nine out of ten people utilized an online travel website for booking. At least 9 out of 10 translates to x ≥ 9, so we calculate P(x ≥ 9) for x = 9 and x = 10. This leads to: P(x ≥ 9) = 10C9 × (0.72^9 × 0.28^(10 - 9)) + 10C10 × (0.72^10 × 0.28^(10 - 10)), resulting in approximately P(x ≥ 9) = 0.183.
3 0
1 month ago
Which statements about the figure must be true? Select three options. A- Line segment A B is bisected by Line segment C D . B- L
tester [12383]

Answer:

C and E

Step-by-step explanation:

3 0
2 months ago
Beth drives 200 miles in 4 hours. She drives the first 18 miles at an average speed of 36 mph. Work out her average speed for th
Zina [12379]

Beth travelled the remaining distance with an average speed of 52 mph

Solution:

Given, Beth drives 200 miles in 4 hours.  

The equation for distance speed is expressed as:

\text { distance }=\text { speed } \times \text { time. }   --- eqn 1

Calculating time spent for 18 miles:

She completes the initial 18 miles at an average speed of 36 mph.  

Distance here equals 18 miles

speed equals 36 mph

Substituting values into eqn 1 yields,

\begin{array}{l}{\rightarrow 18 \text { miles }=36 \mathrm{mph} \times \text { time }} \\\\ {\rightarrow \text { time }=\frac{1}{2} \text { hour }}\end{array}

Determining average speed for the remaining journey:

The distance left to cover is = 200 miles – 18 miles = 182 miles

The time spent on the remaining trip equals the total time minus the duration for the first 18 miles

4 \text { hours }-\frac{1}{2} \text { hours }=\frac{7}{2} \text { hours }

Inserting values into eqn 1 gives us

\begin{array}{l}{182 \text { miles }=\text { average speed } \times \frac{7}{2} \text { hours }} \\\\ {\text { Average speed }=\frac{182}{7} \times 2=52}\end{array}

This confirms that the average speed for the rest of the journey is 52 mph

3 0
3 months ago
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