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2 months ago

A person on a diet loses 1.6 kg in a week. How many micrograms/second (µg/s) are lost?

1 answer:

8 0

To calculate the rate, first convert units properly. Since 1 kilogram equals 1,000,000 micrograms, 1.6 kilograms is 1,600,000 micrograms. One week has 604,800 seconds. Therefore, dividing 1,600,000 micrograms by 604,800 seconds gives the rate. Simplifying, this results in 2.65 µg/s. I hope this answers your question.

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Slick Willy is in traffic court (again) contesting a $50.00 ticket for running a red light. "You see, your Honor, as I was appro

kicyunya [3294]

Slick Willy was traveling at a speed of 61578948 m/s to witness this phenomenon. To arrive at this conclusion, we apply the equation: λ = λ (687 nm) = 570 nm = 61578948 m/s.

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25 days ago

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Two carts are involved in an elastic collision. Cart A with mass 0.550 kg is moving towards Cart B with mass 0.550 kg, which is

Sav [3153]

Answer:

A) $v_b=0.8\ m.s^{-1}$ denotes the resultant velocity of cart B post-collision.

B) $KE_A=0.176\ J$

C) $KE_B=0\ J$

D) $ke_a=0\ J$

E) $ke_B=0.176\ J$

F) Yes, kinetic energy remains conserved in this situation because both colliding bodies have identical mass.

G) Yes, momentum is conserved in every elastic collision.

Explanation:

Given:

mass of car A, $m_a=0.55\ kg$

mass of car B, $m_b=0.55\ kg$

initial velocity of car A, $u_a=0.8\ m.s^{-1}$

final velocity of car A, $v_a=0\ m.s^{-1}$

The question mentions the cars experience an elastic collision:

By applying momentum conservation principles:

$m_a.u_a+m_b.u_b=m_a.v_a+m_b.v_b$

$0.55\times 0.8+0.55\times 0=0.55\times 0+0.55\times v_b$

$v_b=0.8\ m.s^{-1}$ denotes the resulting velocity of cart B after collision.

Initial kinetic energy of cart A:

$KE_A=\frac{1}{2} m_a.u_a^2$

$KE_A=0.5\times 0.55\times 0.8^2$

$KE_A=0.176\ J$

Initial kinetic energy of cart A:

$KE_B=\frac{1}{2} \times m_b.u_b^2$

$KE_B=0.5\times 0.55\times 0^2$

$KE_B=0\ J$

The final kinetic energy of cart A:

$ke_A=\frac{1}{2} m_a.v_a^2$

$ke_a=0.5\times 0.55\times 0^2$

$ke_a=0\ J$

The final kinetic energy of cart B:

$ke_B=\frac{1}{2} m_b.v_b^2$

$ke_B=0.5\times 0.55\times 0.8^2$

$ke_B=0.176\ J$

Yes, kinetic energy is conserved in this case due to both masses being identical in the collision.

Indeed, momentum is consistently conserved in elastic collisions.

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16 days ago

A Honda Civic travels in a straight line along a road. The car’s distance x from a stop sign is given as a function of time t by

serg [3582]

a) Average velocity: 2.8 m/s

b) Average velocity: 5.2 m/s

c) Average velocity: 7.6 m/s

Explanation:

The car's position over time t can be described by

$x(t)=\alpha t^2 - \beta t^3$

where

$\alpha = 1.50 m/s^2$

$\beta = 0.05 m/s^3$

To find the average velocity, we divide the displacement by the elapsed time:

$v=\frac{\Delta x}{\Delta t}$

At time t = 0, the position is:

$x(0)=\alpha \cdot 0^2 - \beta \cdot 0^3 = 0$

At time t = 2.00 s, the position is:

$x(2)=\alpha \cdot 2^2 - \beta \cdot 2^3=5.6 m$

This leads us to the displacement of

$\Delta x = x(2)-x(0)=5.6-0=5.6 m$

The duration for this interval is

$\Delta t = 2.0 s - 0 s = 2.0 s$

Therefore, the average velocity during this period is

$v=\frac{5.6 m}{2.0 s}=2.8 m/s$

At time t = 0, the position is:

$x(0)=\alpha \cdot 0^2 - \beta \cdot 0^3 = 0$

At time t = 4.00 s, the position is:

$x(4)=\alpha \cdot 4^2 - \beta \cdot 4^3=20.8 m$

Thus, the displacement is

$\Delta x = x(4)-x(0)=20.8-0=20.8 m$

The time interval is

$\Delta t = 4.0 - 0 = 4.0 s$

This yields an average velocity of

$v=\frac{20.8}{4.0}=5.2 m/s$

The position at t = 2 s is:

$x(2)=\alpha \cdot 2^2 - \beta \cdot 2^3=5.6 m$

And at t = 4 s it is:

$x(4)=\alpha \cdot 4^2 - \beta \cdot 4^3=20.8 m$

This gives us a displacement of

$\Delta x = 20.8 - 5.6 = 15.2 m$

While the time interval is

$\Delta t = 4.0 - 2.0 = 2.0 s$

So the resulting average velocity is

$v=\frac{15.2}{2.0}=7.6 m/s$

Find out more about average velocity:

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1 month ago

Planting of crops to purify -lucern, shrubs, trees(possible job creation)

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These plants were utilized to eliminate harmful substances from the environment. In today's world, such crops have evolved into a significant asset and can be a source of profit when managed properly, creating multiple job opportunities along the way. Hope this information is useful.

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19 days ago

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A TMS (transcranial magnetic stimulation) device creates very rapidly changing magnetic fields. The field near a typical pulsed-

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It is stated that, in a typical pulsed-field machine, the magnetic field rises from 0 T to 2.5 T within 200 μs. The change in the magnetic field and time interval are relevant here. The diameter is 2.3 cm, translating to a radius of 0.0115 m. As the magnetic field changes, an induced emf occurs within the ring, determined by: E = 5.19 volts. Thus, the induced emf in the ring equates to 5.19 volts, which is the sought solution.

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12 days ago