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Liula
7 days ago
15

Fill in the Blank: The _____ has a very sturdy handle with good leverage for tightening nuts and bolts. It can be used to apply

more torque to a fastener than other bars. A) Breaker Bar B) Speed Handle C) Ratchet D) T-Handle
Engineering
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The top 3 most popular male names of 2017 are Oliver, Declan, and Henry according to babynames. Write a program that modifies th
Viktor [391]

Answer:

The Python code is provided below with suitable comments

Explanation:

# convert list to set

male_names = set(['Oliver','Declan','Henry'])

# get name for removal and addition from user

remove_name = input("Enter remove name: ")

add_name = input("Enter add name: ")

# remove specified name from set

male_names.remove(remove_name)

# add new name to set

male_names.add(add_name)

# sort the resulting set

a = sorted(male_names)

# output the sorted set

print(a)

7 0
3 months ago
You are working in a lab where RC circuits are used to delay the initiation of a process. One particular experiment involves an
pantera1 [306]

Answer:

t'_{1\2} = 6.6 sec

Explanation:

The half-life for the specified RC circuit can be expressed as

t_{1\2} =\tau ln2

where [/tex]\tau = RC[/tex]

t_{1\2} = RCln2

Given t_{1\2} = 3 sec

The circuit has a resistance of 40 ohms, and by adding a new resistor of 48 ohms, the total resistance becomes 40 + 48 = 88 ohms.

Thus, the new half-life is

t'_{1\2} =R'Cln2

Now, divide equation 2 by 1

\frac{t'_{1\2}}{t_{1\2}} = \frac{R'Cln2}{RCln2} = \frac{R'}{R}

t'_{1\2} = t'_{1\2}\frac{R'}{R}

After substituting all values, we can calculate the revised half-life

t'_{1\2} = 3 * \frac{88}{40} = 6.6 sec

t'_{1\2} = 6.6 sec

7 0
2 months ago
Six years ago, an 80-kW diesel electric set cost $160,000. The cost index for this class of equipment six years ago was 187 and
grin007 [323]

Answer:

total expense for the new boiler = $229706.825

total expense for new boiler = $127512

Explanation:

provided information

initial power p1 = 80 kW

price C = $160000

cost index CI 1 = 187

cost index CI 2= 194

capacity factor f = 0.6

subsequent power p2 = 120 kW

present cost = $18000

to determine

total expense and cost for 40 kW

solution

we evaluate CN cost for the new boiler and CO cost for the existing boiler

where x represents the capacity of the new boiler

first we compute the current cost of the old boiler which is

current cost CO = C × \frac{CI 1 }{CI 2 }.............1

substituting the value here

current cost = 160000 × \frac{194 }{187 }

updated current cost = $165989.304

and

employing power sizing strategy for 124 kW

CN/CO = (\frac{p2}{p1} )^{f}...............2

insert value and calculate CN

CN/CO = (\frac{p2}{p1} )^{f}  

CN / 165989.304 = (\frac{120}{80} )^{0.6}  

CN = 211706.825

therefore the new expense = $211706.825

hence

total expense for the new boiler amounts to

total expense = new expense + current cost

total exp = 211706.825 + 18000

boiler expense total = $229706.825

and

concerning a 40 kW unit, the calculated new cost will be

applying equation 2

CN/CO = (\frac{p2}{p1} )^{f}

CN / 165989.304 = (\frac{40}{80} )^{0.6}  

CN = 109512

thus the new cost is $109512

therefore

total expense for the new boiler is

total exp = new cost + current cost

total expense = 109512 + 18000

total cost for the new boiler = $127512

7 0
2 months ago
A spherical hot-air balloon is initially filled with air at 120 kPa and 20°C with an initial diameter of 5 m. Air enters this ba
mote1985 [299]

Answer:

The duration is 17.43 minutes.

Explanation:

Based on the provided information, the initial diameter is 5 m

the velocity is 3 m/s

and the final diameter is 17 m.

To find the solution, we will use the volume change equation expressed as

ΔV = \frac{4}{3} \pi * (rf)^3 - \frac{4}{3} \pi * (ri)^3.............1

where ΔV represents the change in volume, rf is the final radius, and ri is the initial radius.

Calculating ΔV yields

ΔV = \frac{4}{3} \pi * (8.5)^3 - \frac{4}{3} \pi * (2.5)^3

ΔV = 2507 m³.

Thus,

Q = velocity × Area

Q = 3 × π ×(0.5)² = 2.356 m³/s.

Next, the change in time can be expressed as

Δt = \frac{\Delta V}{Q}

Δt = \frac{2507}{2.356}

Δt = 1046 seconds.

Therefore, the total change in time amounts to 17.43 minutes.

8 0
2 months ago
The force of magnitude F acts along the edge of the triangular plate. Determine the moment of F about point O. Find the general
Daniel [329]

Answer:

  M_o = 18.84 N*m clockwise.  

Explanation:

Given:

- Force F = 120 N

- Length b = 610 mm

- Height h = 330 mm

Required:

Calculate the moment M_o at the origin and its direction:

Solution:

- The force is divided into components F_x and F_y along the base b and height h, respectively:

                    F_x = F*cos(Q)

                    F_x = F*(h / sqrt(h² + b²))

                    F_x = 120*(330 / sqrt(330² + 610²))

                    F_x = 57.098 N

- The F_y component can be excluded as it passes through the origin, resulting in zero moment.

- The moment at point O is calculated as:

                     M_o = F_x * h

                     M_o = 57.098*.33

                    M_o = 18.84 N*m clockwise.  

3 0
2 months ago
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