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nikklg
25 days ago
13

You are working in a lab where RC circuits are used to delay the initiation of a process. One particular experiment involves an

RC circuit with a half-life of t1/2 = 3.00 s. Your supervisor is concerned that the initiation of the process is occurring too soon and that the half-life needs to be extended. He asks you to change the resistance of the circuit to make the half-life longer. All you can find in the supply room is a single 48.0 Ω resistor. You look at the RC circuit and see that the resistance is 40.0 Ω. You combine the new resistor with the old to extend the half-life of the circuit. Determine the new half-life (in s).
Engineering
1 answer:
pantera1 [220]25 days ago
7 0

Answer:

t'_{1\2} = 6.6 sec

Explanation:

The half-life for the specified RC circuit can be expressed as

t_{1\2} =\tau ln2

where [/tex]\tau = RC[/tex]

t_{1\2} = RCln2

Given t_{1\2} = 3 sec

The circuit has a resistance of 40 ohms, and by adding a new resistor of 48 ohms, the total resistance becomes 40 + 48 = 88 ohms.

Thus, the new half-life is

t'_{1\2} =R'Cln2

Now, divide equation 2 by 1

\frac{t'_{1\2}}{t_{1\2}} = \frac{R'Cln2}{RCln2} = \frac{R'}{R}

t'_{1\2} = t'_{1\2}\frac{R'}{R}

After substituting all values, we can calculate the revised half-life

t'_{1\2} = 3 * \frac{88}{40} = 6.6 sec

t'_{1\2} = 6.6 sec

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Retype the below code. Fix the indentation as necessary to make the program work. if 'New York' in temperatures: if temperatures
Daniel [215]

Answer: Below is the correctly formatted code:

if 'New York' in temperatures:

if temperatures['New York'] > 90:

   print('The city is melting!')

else:

   print('The temperature in New York is', temperatures['New York'])

else:

   print('The temperature in New York is unknown.')

Explanation:

This is the entire program:

temperatures = {

   'Seattle': 56.5,

   'New York': 105,

   'Kansas City': 81.9,

   'Los Angeles': 76.5

}

if 'New York' in temperatures:

if temperatures['New York'] > 90:

   print('The city is melting!')

else:

   print('The temperature in New York is', temperatures['New York'])

else:

   print('The temperature in New York is unknown.')

The output will be:

The city is melting!

This program mainly comprises nested if statements. The first check determines if 'New York' exists within the temperature data. When confirmed, it moves to another if statement to see if New York's temperature exceeds 90. If true, it outputs the message, "The city is melting!". If false, it presents the actual temperature of New York. If neither condition is satisfied, it defaults to showing that the temperature is unknown. Given that New York's temperature is 105, the output reflects that the city is melting!

Proper indentation is crucial in Python, as it distinguishes code blocks without needing brackets, enhancing readability. Observe how the nested if statements are structured within the outer if statement. The else statements align appropriately beneath their respective if declarations, and print statements follow the necessary indentation.

4 0
1 month ago
PDAs with two stacks are strictly more powerful than PDAs with one stack. Prove that 2-stack PDAs are not a valid model for CFLs
iogann1982 [279]

Answer:

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Explanation:

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2 days ago
Gold and silver rings can receive an arc and turn molten. True or False
grin007 [219]
That statement is incorrect!
The claim is untrue
8 0
1 month ago
Read 2 more answers
Number pattern Write a recursive method called print Pattern() to output the following number pattern. Given a positive integer
alex41 [274]

Response:

Refer to the explanation

Clarification:

Code:

import java.util.Scanner;

public class NumberPattern {

public static int x, count;

public static void displayNumPattern(int num1, int num2) {

if (num1 > 0 && x == 0) {

System.out.print(num1 + " ");

count++;

displayNumPattern(num1 - num2, num2);

} else {

x = 1;

if (count >= 0) {

System.out.print(num1 + " ");

count--;

if (count < 0) {

System.exit(0);

}

displayNumPattern(num1 + num2, num2);

}

}

}

public static void main(String[] args) {

Scanner scnr = new Scanner(System.in);

int num1;

int num2;

num1 = scnr.nextInt();

num2 = scnr.nextInt();

displayNumPattern(num1, num2);

}

}

See attached example output

3 0
19 days ago
Read 2 more answers
The rigid beam is supported by a pin at C and an A992 steel guy wire AB of length 6 ft. If the wire has a diameter of 0.2 in., d
Mrrafil [253]

Answer:

Change in length = 0.0913 in

Explanation:

Given data:

Length = 6 ft

Diameter = 0.2 in

Load w = 200 lb/ft

Solution:

We start by applying the equilibrium moment about point C, expressed as

∑M(c) = 0.............1

This can be used to find the force in AB.

10× 200 × ( 5) - (T cos(30)) × 10 = 0

Solving gives us

Tension in wire T(AB) = 1154.7 lb

We also know the modulus of elasticity for A992 is

E = 29000 ksi

And the area will be

Area = \frac{\pi }{4}\times 0.2^2

The change in length is expressed as

Change in length = \frac{PL}{AE}.........2

Substituting values results in

Change in length = \frac{1154.7 \times 6 \times 12}{\frac{\pi }{4}\times 0.2^2 \times 29000 \times 1000}

Change in length = 0.0913 in

8 0
26 days ago
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