How many atoms of ^6Li are there in 12.3 g of ^6Li?

Answer:

The mass of 22-Na included in the sample amounts to 0.0599 g

Explanation:

The total mass of the isotope mixture is 1.8385g.

It has an apparent mass of 22.9573 u.

For 23-Na, the relative atomic mass is 22.9898 u, while for 22-Na it is 21.9944 u.

Let the relative abundance of 23-Na be denoted as X.

This means that the relative abundance of 22-Na can be expressed as (1-X).

The equation formed is 21.9944 (1-X) + 22.9898 X = 22.9573.

Rearranging gives: 21.9944 - 21.9944X + 22.9898X = 22.9573.

Which simplifies to 22.9898X - 21.9944X = 22.9573 - 21.9944.

Hence, 0.9954X = 0.9639, leading to X = 0.9674.

The relative abundance of 23-Na is now identified as 0.9674.

Consequently, the relative abundance of 22-Na is 1 - 0.9674 = 0.0326.

Now, the mass of 22-Na contained within the 1.8385g sample is determined by

Relative abundance of 22-Na multiplied by the mass of the total sample = 0.0326 × 1.8385g = 0.0599 g.

Option d is the correct choice, as both belong to the alkali metals category (group one).

Clarification:

The Na2 molecules comprise atoms that are connected by a purely covalent bond since both atoms have the same electronegativity.

Metallic bonding only manifests when several atoms cluster together. Such aggregates may not tend to be stable, as larger masses of material typically exhibit greater stability thermodynamically. Therefore, they often merge until a significant metal chunk is formed.

In some ways, metallic bonding can be considered a variant of covalent bonding, but it is more communal—delocalized across numerous atoms—and electron deficient (there are more energy states than available electrons, which contributes to conductive traits). This implies that the term “metallic bond” might appear contradictory, akin to referring to a forest with a single tree.

Engage me in comments

The coefficients in a balanced equation indicate the relationship between the moles of reactants and products. In this case, four moles of hydrochloric acid react with one mole of oxygen to yield two moles of chlorine and water. Therefore, the mole ratio of hydrochloric acid to chlorine is 2:1. To calculate the number of moles, you divide the mass by the mass of a single mole. Cl2 = 2 * 35.45 = 70.9 grams. Thus, Number of moles = 335 ÷ 70.9, which is roughly 4.72 moles. The amount of hydrochloric acid would then be double that figure.

Answer:

If energy is absorbed more quickly than it can be dissipated through radiation, convection, or conduction, its temperature will rise. The type of light does not matter.

Explanation: