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butalik
10 days ago
14

How many atoms of ^6Li are there in 12.3 g of ^6Li?

Chemistry
1 answer:
alisha [964]10 days ago
8 0

Answer:6.94

Explanation:Atomic mass of Li = 6.94

To find the number of atoms: 12.6 g Li x 1 mole/6.94 g x 6.02x10^23 atom/mole = 1.09x10^24 atoms

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If the 3.90 m solution from Part A boils at 103.45 ∘C, what is the actual value of the van't Hoff factor, i? The boiling point o
alisha [964]
<span>Some solutions demonstrate colligative properties, which rely on the quantity of solute in a solvent. To find the elevation in boiling point, we use the formula:

</span><span>ΔT(boiling point)  = (Kb)mi

where Kb represents a constant, m is the solution's molality, and i is the van't Hoff factor.

From the provided information, we can easily determine i as follows:

</span>ΔT(boiling point)  = (Kb)mi
103.45 - 100  = (0.512)3.90i
i = 1.73 <-------van't Hoff factor
7 0
8 days ago
A hardware salesman measures the mass of a box containing
lorasvet [956]
Step 1: To find the mass of a single washer, divide the total measured mass by the number of washers \frac{0.4168}{1000} =0.0004168\ Kg 0.0004168kg=4.168*10^{-4} kg. Step 2: Convert kilograms to milligrams knowing 1 kg=1*10^{6} mg; thus 4.168*10^{-4}*10^{6} =4.168*10^{2}mg=416.8 mg resulting in the final answer 416.8 mg.
8 0
15 days ago
Read 2 more answers
The reaction between nitrogen dioxide and carbon monoxide is NO2(g)+CO(g)→NO(g)+CO2(g)NO2(g)+CO(g)→NO(g)+CO2(g) The rate constan
eduard [944]

Response: The rate constant at 525 K is, 0.0606M^{-1}s^{-1}

Rationale:

Based on the Arrhenius equation,

K=A\times e^{\frac{-Ea}{RT}}

or,

\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_1 = rate constant when 701K = 2.57M^{-1}s^{-1}

K_2 = rate constant when 525K =?

Ea = activation energy for the process = 1.5\times 10^2kJ/mol=1.5\times 10^5J/mol

R = gas constant = 8.314 J/mole.K

T_1 = initial temperature = 701 K

T_2 = final temperature = 525 K

Substituting the provided values into this formula yields:

\log (\frac{K_2}{2.57M^{-1}s^{-1}})=\frac{1.5\times 10^5J/mol}{2.303\times 8.314J/mole.K}[\frac{1}{701K}-\frac{1}{525K}]

K_2=0.0606M^{-1}s^{-1}

Thus, the rate constant at 525 K is, 0.0606M^{-1}s^{-1}

8 0
2 days ago
How can a piece of wood floating on water illustrate the condition of lowest potential energy and maximum
Tems11 [846]

Answer:

By reducing the height of the center of gravity of the object in relation to its center of buoyancy

Explanation:

In the field of hydrostatics, for a floating object, the state of equilibrium corresponds to either a peak or a trough in potential energy. Stability in equilibrium occurs when the potential energy is minimized. Achieving a lower position of the center of gravity of the floating object compared to its center of buoyancy creates a stable equilibrium arrangement.

4 0
11 days ago
A metallic object holds a charge of −4.8 × 10−6 C. What total number of electrons does this represent? (e = 1.6 × 10−19 C is the
Anarel [852]

Answer:

n=3.0\times 10^{13}

Explanation:

Charge of one electron = -1.6\times 10^{-19}\ C

The formula for calculating charge is:

Charge=n\times q_e

Given that: Charge = -4.8\times 10^{-6}\ C

-4.8\times 10^{-6}=n\times (-1.6\times 10^{-19})

n=\frac{4.8\times 10^{-6}}{1.6\times 10^{-19}}=3.0\times 10^{13}

Total electrons, n = 3.0\times 10^{13}

5 0
13 days ago
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