If 8.00 g NH4NO3 is dissolved in 1000 g of water, the water decreases in temperature from 21.00 degrees Celsius to 20.39 degrees

Respuesta:

737.52 mL de agua

Justificación:

En este escenario, es necesario aplicar la fórmula de molaridad de una solución, que es:

M = moles / V

Donde:

V: Volumen de la solución.

Ya que deseamos determinar la cantidad de agua, en otras palabras, buscamos el volumen del solvente que se utilizó para crear los 800 mL de la disolución.

Una disolución se compone de un soluto y un solvente. El soluto que tenemos es nitrato de plata. Utilizando la fórmula mencionada, calculamos los moles de soluto y luego su masa. Tras eso, calculamos el volumen a partir de la densidad y, al final, determinamos la cantidad de solvente de esta manera:

V ste = Vsol - Vsto

Primero, vamos a calcular los moles de soluto:

moles = M * V

moles = 2 * 0.800 = 1.6 moles

Con este número de moles, obtenemos la masa utilizando el peso molecular que es 169.87 g/mol:

m = moles * PM

m = 1.6 * 169.87 = 271.792 g

Usando el valor de densidad, procederemos a calcular el volumen de soluto utilizado:

d = m/V

V = m/d

V = 271.792 / 4.35

V = 62.48 mL

Por último, la cantidad de agua requerida es:

V agua = 800 - 62.48

V agua = 737.52 mL

Density is defined as the "mass per unit volume" of an object.

Thus, for an object weighing 100 grams with a volume of 100 milliliters, the density calculates to 100 grams / 100 ml.

When weighing the object, if there is water on the scale's surface, it will contribute additional weight, making the object seem heavier than its actual mass. Consequently, you might mistakenly conclude that the density is GREATER than it truly is.

For instance, if there were 5 ml of water on the scale, with water's density being 1 gram per milliliter (1 g/ml), it would add 5 grams to the object's weight. Using the previous example, the object's mass appears as 105 grams instead of 100 grams. Thus, you would calculate:

density = mass / volume
density = 105 grams / 100 ml
density = 1.05 g/ml

Thus, the effect on density would be to misleadingly suggest it is greater.

I hope this is helpful!

Best of luck

We need to calculate the volume of Gold, assuming its mass matches that of copper.

Given information:

Density of Copper = 8.96 g/ml.
Volume of Copper = 141 ml.
Mass of Gold = Mass of Copper.
Density of Gold = 19.3 g/ml.

To find copper's mass, we use the density equation:
Density = mass/volume.

To find mass of copper:
Mass of copper = Density of Copper * Volume of Copper.
Mass of copper = 8.96 g/ml * 141 ml = 1263.36 g.
Thus,
Mass of gold = Mass of copper = 1263.36 g.
Now, using the density formula for gold to get its volume:
Volume of gold = Mass of gold / Density of gold.
Volume of gold = 1263.36 g / 19.3 g/ml = 65.46 mL.

Consequently, the volume of gold required to match the mass of copper is 65.46 mL.

Answer:

The correct choice is: option A.

Justification:

To address this inquiry, we need to evaluate the total number of electrons each orbital can accommodate.

  Orbital                         Number of electrons

   s                                   2

   p                                  6

   d                                 10

   f                                  14

Provided options:

A. 1s² 2s² 2p⁶ 3s²                 This configuration is valid as it aligns with the permitted number of electrons in each orbital and follows the correct sequence.

B. 1s² 2s² 2p⁶ 3s² 3d⁴          This configuration is not accurate because

                                         3d⁴ should follow 3p.

C. 1s² 2s² 2d¹⁰ 2p³                This is incorrect since 2d¹⁰ is not a valid orbital.

D. 1s² 2s^s 2p³ 2d¹⁰            This option contains two errors; s as an exponent does not exist, and 2d¹⁰ is also an invalid description.

<span>Reaksi antara besi dan asam klorida menghasilkan besi (II) klorida serta gas hidrogen.</span>