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timurjin
3 months ago
14

What volume of gold would be equal in mass to a piece of copper with a volume of 141 ml? the density of gold is 19.3 g/ml; the d

ensity of copper is 8.96 g/ml?
Chemistry
1 answer:
alisha [2.9K]3 months ago
8 0

We need to calculate the volume of Gold, assuming its mass matches that of copper.

Given information:

Density of Copper = 8.96 g/ml.
Volume of Copper = 141 ml.
Mass of Gold = Mass of Copper.
Density of Gold = 19.3 g/ml.

To find copper's mass, we use the density equation:
Density = mass/volume.

To find mass of copper:
Mass of copper = Density of Copper * Volume of Copper.
Mass of copper = 8.96 g/ml * 141 ml = 1263.36 g.
Thus,
Mass of gold = Mass of copper = 1263.36 g.
Now, using the density formula for gold to get its volume:
Volume of gold = Mass of gold / Density of gold.
Volume of gold = 1263.36 g / 19.3 g/ml = 65.46 mL.

Consequently, the volume of gold required to match the mass of copper is 65.46 mL.

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Some oxygen gas takes up a volume of 2.00 liters at 0.99 atm and 273 K. Its volume doubles and its temperature decreases to 137
KiRa [2933]
The response to your inquiry is: option B. 0.25 atm

Explanation:

To solve this issue, the combined gas law must be applied:

P₁V₁ = P₂V₂ / T₁T₂

The data is as follows: P1 = 0.99 atm, V1 = 2 L, T1 = 273 K, P2 =?, V2 = 4 L, T2 = 137 K.

By isolating P2 in the equation, you find

P2 = P1V1T2 / T1V2. Substituting in the numbers gives: P2 = (2 x 0.99 x 137)/(273 x 4). The resulting P2 equates to approximately 0.25 atm.

5 0
3 months ago
Read 2 more answers
A compound that is composed of carbon, hydrogen, and oxygen contains 70.6% C, 5.9% H, and 23.5% O by mass. The molecular weight
Tems11 [2777]

Answer: The molecular formula will be C_8H_8O_2

Explanation:

When percentages are provided, we assume the total mass to be 100 grams.

Thus, the mass of each element corresponds to the specified percentage.

Mass of C= 70.6 g

Mass of H = 5.9 g

Mass of O = 23.5 g

Step 1: convert given masses to moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{70.6g}{12g/mole}=5.9moles

Moles of H =\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{5.9g}{1g/mole}=5.9moles

Moles of O =\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{23.5g}{16g/mole}=1.5moles

Step 2: For determining the mole ratio, divide each molar amount by the smallest number of moles calculated.

For C = \frac{5.9}{1.5}=4

For H = \frac{5.9}{1.5}=4

For O =\frac{1.5}{1.5}=1

The resulting ratio of C: H: O= 4: 4: 1

Hence, the empirical formula obtained is C_4H_4O

The empirical weight is calculated as C_4H_4O = 4(12)+4(1)+1(16)= 68g.

The molecular weight = 136 g/mole

Now the molecular formula needs to be obtained.

n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{136}{68}=2

The molecular formula can be derived as=2\times C_4H_4O=C_8H_8O_2

4 0
3 months ago
Which procedure cannot be performed on a hot plate, requiring a Bunsen burner instead
Tems11 [2777]

Answer: The process of heating a crucible to eliminate moisture from a hydrate.

Explanation:

The available choices are:

a. Heating a solvent to aid in the dissolution of a solute.

b. Heating a solid in isolation to remove moisture.

c. Bringing water to a boil for use in a water bath.

d. Heating a crucible to eliminate moisture from a hydrate.

Possible actions that can be done on a hot plate include:

a. Heating a solvent to assist a solute in dissolving.

b. Heating a solid in isolation to dry it.

c. Heating water to boiling for a water bath.

However, it's important to note that using a hot plate for heating a crucible to remove water from a hydrate is not advisable. Silica or ceramic materials are not meant to be heated on a hot plate.

Consequently, the correct procedure is heating a crucible to remove water from a hydrate.

4 0
4 months ago
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