Answer:
The right responses are "bulb or pump; meniscus; outside".
Explanation:
Pipets are essential tools in laboratory settings. They are designed for transferring liquids from one vessel to another. First, a bulb or pump is attached to the top to empty the pipet completely. Next, fill the pipet until the meniscus (the curved top of the liquid) aligns with the measurement line corresponding to the volume needed. Finally, dispense the liquid into a second container and make sure to eliminate the last drop beyond the pipet tip.
The mixture’s density is 1.57 g/cm³.
Step 1: Determine the mass of the butter.
Step 2: Determine the mass of the sand.
Step 3: Determine the density of the mixture.
Total mass = 0.860 g + 2.28 g = 3.14 g.
Total volume = 1 cm³ + 1 cm³ = 2 cm³
E = mc²
where E = energy produced
m = mass of the nucleus
C = speed of light
m = 9.106 x 10⁻³ x 1.67 x 10⁻²⁷ kg
C = 3 x 10⁸ m/s, thus C² = 9 x 10¹⁶
E = 1.37 x 10⁻¹² J
(c) Cu + S → CuS is classified as a redox reaction
Explanation:
The following reactions are presented:
(a) K₂CrO₄ + BaCl₂ → BaCrO₄ + 2 KCl
(b) Pb²⁺ + 2 Br⁻ → PbBr₂
(c) Cu + S → CuS
Reaction (c) represents a redox reaction, as the oxidation states of the elements are changing. In this case:
Cu + S → CuS
In its elemental form, Cu has an oxidation state of 0, while in CuS (copper sulfide), its oxidation state changes to +2.
Similarly, S in its elemental form has an oxidation state of 0 and is -2 in CuS (copper sulfide).
Learn more about:
redox reactions
Answer:
Explanation:
The relationship between the new temperature scale and the absolute temperature scale is defined as follows
Aw = 2 K
for K = 273.15 (the freezing point of water on the absolute scale)
Aw = 2 x 273.15 = 546.3 K
Each division of the new scale is equivalent to half that of each division on the absolute scale
each division of the new scale is minimal.
The value of R = 8.314 J per mole per K
Here, per K corresponds to 2Aw
Hence, the value of R in the new scale = 8.314/2 J per mole per Aw
= 4.157 J per mole per Aw
k = R / N
= 4.157 / 6.02 x 10²³
= .69 x 10⁻²³
= 6.9 x 10⁻²⁴ J per molecule per Aw .
