A child is sliding a toy block (with mass = m) down a ramp. The coefficient of static friction between the block and the ramp is

0.25. When the block is halfway down the ramp, the child pushes down on the block perpendicular to the plane, halting it. What is the minimum force the child must apply to keep the block from starting to slide down the ramp?

Physics

You might be interested in

The amount of kinetic energy an object has depends on its mass and its speed. Rank the following sets of oranges and cantaloupes

Sav [3153]

mass₃<mass₁=mass₅<mass₂=mass₄

Explanation:

Data points:-

1. mass: m speed: v

2. mass: 4 m speed: v

3. mass: 2 m speed: ¼ v

4. mass: 4 m speed: v

5. mass: 4 m speed: ½ v

We know that the formula for Kinetic energy (KE) is ½ mv²

Where m represents the mass of the object

v represents the object's velocity

The KE of Body 1(mass₁) = ½*m*v² = mv²/2

KE of Body 2(mass₂) = ½*4m*v² = 2mv²

KE of Body 3(mass₃) = ½*2m*(1/4v)² = mv²/16

KE of Body 4(mass₄) = ½*4m*v ² = 2mv ²

KE of Body 5(mass₅) = ½*4m*(1/2v)² = mv²/2

</psubstituting>

6 0

2 months ago

The weight of your car will also affect its _____.

inna [3103]

Stopping distance.

3 0

2 months ago

Read 2 more answers

An 800-N billboard worker stands on a 4.0-m scaffold weighing 500 N and supported by vertical ropes at each end. How far would t

Maru [3345]

Answer:

2.5 m

Explanation:

Billboard worker's weight = 800 N

Number of ropes = 2

Length of scaffold = 4 m

Weight of scaffold = 500 N

Tension present in rope = 550 N

The total torques will be

$-800(4-x)-500\times 2+550\times 4=0\\\Rightarrow -800(4-x)=500\times 2-550\times 4\\\Rightarrow -800(4-x)=-1200\\\Rightarrow -x=\dfrac{1200}{800}-4\\\Rightarrow -x=-2.5\\\Rightarrow x=2.5\ m$