Answer:
Domain = [0, 50]
Range = [0, 3250]
Step-by-step explanation:
A function illustrates the relationship between two variables (independent and dependent). The independent variable depends on nothing else, serving as the function's input, while the dependent variable relies on the independent variable, acting as the output.
The domain of a function includes all possible input variables (independent variable), and the range encompasses all potential output variables (dependent variables).
For the function C(p) = 65p, p represents the independent variable and C(p) constitutes the dependent variable.
As the hall accommodates a maximum of 50 individuals, the domain of this function is defined as [0, 50]
C(0) results in 65(0) = 0 and C(50) results in 65(50) = 3250
Thus, the range of this function is [0, 3250]
Response: (0.8115, 0.8645)
Step-by-step outline:
Define p as the proportion of individuals who leave one space after a sentence.
Provided: Sample size: n= 525
Number of respondents indicating they leave one space: 440
Thus, the sample proportion is: 
The z-score for a 90% confidence interval is: 1.645
The formula for determining the confidence interval:


Consequently, a 90% confidence interval for the proportion of people who leave one space after a period is: (0.8115, 0.8645)
Answer:
The correct answer is;
A. 0.17
Step-by-step explanation:
Here are the provided details;
The average time taken for a cashier to handle an order, μ = 276 seconds
The deviation from the average, σ = 38 seconds
The z-score for an order processing time of x = 240 seconds can be calculated as follows;

Thus;

The resulting probability
P(z = -0.9474) = 0.17361
Hence, the estimated proportion of orders processed in under 240 seconds is roughly 0.17361 or 0.17 when rounded to two decimal places.
Answer:
The value equals 1
Step-by-step explanation:
Consider the expression

Recall that


For two complementary angles A and B (where A+B=90°),
the identity is
cos(A) = sin(B)
Here, 26° and 64° are complementary angles, so

Substituting values,


From this, we find

By substitution,
