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ANEK
1 day ago
13

The formula to determine energy is uppercase E = one-half m v squared. What is the formula solved for v?

Mathematics
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Toby goes on holiday to Geneva, Switzerland. In Geneva, Toby sees a watch costing 193.75 CHF (Swiss Francs). In Manchester, an i
lawyer [12517]
The watch is less expensive in Geneva, Switzerland by £20. Step-by-step explanation: To identify the city where the watch is cheaper, we need to convert the watch's price to the same currency. Since pounds are utilized in part b of the question, using this currency would simplify the calculations. In Geneva, the watch's price is 193.75 CHF from our conversion: £1 = 1.55 CHF, thus, £x = 193.75 CHF. By cross-multiplying, we solve for x: (193.75 * 1) / 1.55 = 193.75/1.55 = £125. This demonstrates that the watch is cheaper in Geneva and more expensive in Manchester. To find out by how much, we simply deduct the Geneva price from the Manchester price: 145 - 125 = £20 cheaper.
3 0
1 month ago
A movie is 1 7/8 hours long. After 45 minutes, how much of the movie is left?
Leona [12618]
The result is 67.5 minutes or 1 hour and 8 minutes remaining!
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2 months ago
Elias’s teacher has given him a rectangle that is 15 feet by 20 feet. She has asked him to create a new rectangle using a scale
Inessa [12570]
No, as the fraction equates to a whole number. Thus, it would actually be an increase.
8 0
2 months ago
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Identify the range of the function shown in the graph
Leona [12618]

The domain refers to all potential input values, specifically represented by the x-axis on a graph. Conversely, the range includes all possible output values, depicted along the y-axis.


The graph clearly extends horizontally from (-∞,∞) on the x-axis, indicating that its domain is (-∞,∞).


Similarly, it can be seen that the graph stretches vertically from (-∞,∞) on the y-axis, denoting that the range is also (-∞,∞).


This indicates the function includes an infinite array of values. Therefore, there are no limitations on either the domain or the range for this function.

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2 months ago
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