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olga2289
10 days ago
15

The high school soccer team can have no more than 26 players. Write and solve an inequality to determine how many more players c

an make the team if the coach has already chosen 17.
Mathematics
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If 30,000 cm2 of material is available to make a box with a square base and an open top, what is the largest possible volume (in
Inessa [12570]

Answer:

The highest achievable volume for the box is 2000000 cubic meters.

Step-by-step explanation:

Below is an outline of the volume (V), measured in cubic centimeters, and surface area (A_{s}), measured in square centimeters, for a box featuring a square base:

A_{s} = l^{2}+h\cdot l (1)

V = l^{2}\cdot h (2)

Where:

l - The length of the base's side, in centimeters.

h - The height of the box, in centimeters.

Using (2), we isolate h in the formula:

h = \frac{V}{l^{2}}

Then, we substitute into (1) and simplify the outcome:

A_{s} = l^{2}+ \frac{V}{l}

A_{s}\cdot l = l^{3}+V

V = A_{s}\cdot l -l^{3} (3)

Next, we calculate the first and second derivatives of this expression:

V' = A_{s}-3\cdot l^{2} (4)

V'' = -6\cdot l (5)

If V' = 0 and A_{s} = 30000\,cm^{2}, then we find that the critical value for the base's side length is:

30000-3\cdot l^{2} = 0

3\cdot l^{2} = 30000

l = 100\,cm

Subsequently, we assess this outcome using the second derivative's expression:

V'' = -600

According to Second Derivative Test, this critical value signifies an absolute maximum. Consequently, the largest volume obtainable for the box is:

V = 30000\cdot l - l^{3}

V = 2000000\,cm^{3}

The highest achievable volume for the box is 2000000 cubic meters.

4 0
2 months ago
Student researchers Haley, Jeff, and Nathan saw an article on the Internet claiming that the average vertical jump for teens was
tester [12383]

Answer:

At the α = 0.10 level, there is no substantial evidence indicating that the average vertical jump for students at this school differs from 15 inches.

Step-by-step explanation:

A hypothesis test is necessary to verify the assertion that the average vertical jump of students diverges from 15 inches.

The null and alternative hypotheses are:

H_0: \mu=15\\\\H_a: \mu\neq15

The significance level is set at 0.10.

The sample mean recorded is 17, and the sample standard deviation is 5.37.

The degrees of freedom are calculated as df=(20-1)=19.

The t-statistic is:

t_{19}=\frac{M-\mu}{s_M/\sqrt{n}} =\frac{17-15}{5.37/\sqrt{20}}=\frac{2}{5.37/4.47} =2/1.20=1.67

The two-tailed P-value corresponding to t=1.67 is P=0.11132.

<pSince this P-value exceeds the significance level, the result is not significant. Therefore, the null hypothesis remains unchallenged.

At the α = 0.10 level, there is no compelling evidence that the average vertical jump of students at this school deviates from 15 inches.

7 0
3 months ago
Given: ΔABC, AC = BC, AB = 3 CD⊥ AB, CD = 3 Find: AC
Leona [12618]

Answer:

3\sqrt{5}/2

Step-by-step explanation:

Given that AC = BC, this is an isosceles triangle.

Since CD is perpendicular to AB, we find AD = DB = 0.5AB = 3/2

Now considering triangle ACD,[TAG_17]]

we will use Pythagoras' theorem,

AC = \sqrt{AD^{2} + CD^{2} }

AC = 3\sqrt{5}/2

:-)

4 0
2 months ago
Read 2 more answers
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