A 0.10 kg piece of copper at an initial temperature of 95°c is dropped into 0.20 kg of water contained in a 0.28 kg aluminum cal

The torque resulting from a force is expressed as τ= F r into the blade. The force's moment is mathematically represented as τ = F x r, where the bold terms signify vectors. We can express this in terms of magnitude as τ = F r sin θ. In our scenario, since the force is tangential to the wheel, the angle between F and the radius is 90º, with sin 90 = 1. Hence, τ= F r. The torque's direction can be determined using the right-hand rule, where fingers curling in accordance with the torque direction from force to radius, with the thumb indicating the torque's direction. For a clockwise rotation, the fingers curl in that direction, and the thumb points inward toward the blade, indicating the direction of the torque.

Result: -50.005 kJ

Details:

Provided Data

mass of the system = 10 kg

work done = 0.147 kJ/kg

Elevation change

initial speed

Final Speed

Specific internal Energy

according to the first Law of thermodynamics

where KE represents kinetic energy

PE indicates potential energy

U denotes internal Energy

Q = 1.47 + 3.375 - 4.850 - 50

Q = -50.005 kJ

Para calcular el peso utilizamos la fórmula:


Cuando tenemos dos cuerpos, empleamos la fórmula de la gravedad general:

Donde:
G = constante de gravedad =
Mp = masa de la persona = 882 / 9.81= 89.9kg
ME = masa de la Tierra =
r = distancia entre la Tierra y la persona

A partir de estas dos fórmulas, deducimos que los lados izquierdos son equivalentes, por lo tanto, los lados derechos también deben serlo.


Resolviendo esta ecuación para r:

r=6371116m = 6371.116km

Esta es la distancia desde el centro de la Tierra. El radio de la Tierra es 6370km y la altura sobre la superficie es 6371.116 - 6370 = 1.116km o 1116m.

B = µo*N*I/2r  

Thus, B = 4πx10^-7*150*1.6/2*3.5 = 4.31x10^-5T