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vladimir2022
5 days ago
7

When a 12.0-V battery causes 2.00 μC of charge to flow onto the plates of an air-filled capacitor, how much work did the battery

do?
Physics
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A positive charge moves in the direction of an electric field. Which of the following statements are true?
kicyunya [3294]

Answer:

The potential energy tied to the charge diminishes.

The electric field performs negative work on the charge.

Explanation:

3 0
2 months ago
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A wildlife researcher is tracking a flock of geese. The geese fly 4.0 km due west, then turn toward the north by 40° and fly ano
serg [3582]

Answer:

(a). The distance traveled is 7.06 km towards the west.

(b). Their displacement magnitude is 7.51 km.

Explanation:

The information given states that,

The geese initially move 4.0 km directly west, then alter course to the north at a 40° angle, covering an additional 4.0 km.

Based on the diagram,

(a). To determine the distance

We will apply the distance formula

AD=AB+BD

Insert the values into the equation

D= 4+4.0\cos40^{\circ}

D=7.06\ km

The resultant distance is 7.06 km westward.

(b). We will find the total displacement's magnitude

Using the displacement formula

AC=\sqrt{(CD)^2+(AD)^2}

Insert the values into the equation

AC=\sqrt{(4.0\sin40)^2+(7.06)^2}

AC=7.51

The total displacement magnitude is 7.51 km.

In conclusion, (a). The traveled distance is 7.06 km towards the west.

(b). The magnitude of their total displacement is 7.51 km.

7 0
2 months ago
Light-rail passenger trains that provide transportation within and between cities speed up and slow down with a nearly constant
Yuliya22 [3333]

Answer:

v_f = 13m/s + 0.75 \frac{m}{s^2} * 16 s= 13 m/s +12m/s = 25 m/s

Explanation:

In this scenario, we determine the initial velocity as follows:

v_i = 7 \frac{m}{s}

The final velocity in this instance can be expressed as:

v_f = 13 \frac{m}{s}

It is noted that transitioning from 7m/s to 13m/s takes 8 seconds. We can apply a specific kinematic equation to find the acceleration for the first part of the journey:

v_f = v_i +at

Solved for acceleration, we find:

a = \frac{v_f -v_i}{t} = \frac{13 m/s -7 m/s}{8 s}= 0.75 \frac{m}{s^2}

For the subsequent route, we assume constant acceleration and that the train continues for 16 seconds, beginning with an initial velocity of 13m/s from the previous segment, allowing us to calculate the final speed via the following formula:

v_f = v_ i +a t

Substituting into the equation yields:

v_f = 13m/s + 0.75 \frac{m}{s^2} * 16 s= 13 m/s +12m/s = 25 m/s

5 0
3 months ago
A fan that is switched on for 1 minute uses 500 W usefully but also wastes 300 W through the emission of sound and heat. What's
Ostrovityanka [3204]

Explanation:

Efficiency can be expressed as the ratio of useful output to the total power consumed. E = \frac{useful}{total}

The fan delivers 500W as useful output while wasting 300W. Thus, the overall power consumed equals 800W (500 + 300).

6 0
1 month ago
A soft drink (mostly water) flows in a pipe at a beverage plant with a mass flow rate that would fill 220 cans, 0.355 - l each,
Keith_Richards [3271]
Flow rate calculations yield 220 cans, each with a volume of 0.355 l, leading to 78.1 l/min or 1.3 l/s or 0.0013 m³/s.

At Point 2:
A2 = 8 cm² = 0.0008 m²
V2 = Flow rate/A2 = 0.0013/0.0008 = 1.625 m/s
P1 = 152 kPa = 152000 Pa

At Point 1:
A1 = 2 cm² = 0.0002 m²
V1 = Flow rate/A1 = 0.0013/0.0002 = 6.5 m/s
P1 =?
Height = 1.35 m

Using Bernoulli’s principle;
P2 + 1/2 * V2² / density = P1 + 1/2 * V1² / density + density * gravitational acceleration * height
=> 152000 + 0.5 * (1.625)² * 1000 = P1 + 0.5 * (6.5)² * 1000 + (1000 * 9.81 * 1.35)
=> 153320.31 = P1 + 34368.5
=> P1 = 1533210.31 - 34368.5 = 118951.81 Pa = 118.95 kPa
3 0
3 months ago
Read 2 more answers
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