A thick-walled tube of stainless steel having a k = 21.63 W/m∙K with dimensions of 0.0254 m ID and 0.0508 m OD is covered with 0
.0254 m thick layer of an insulation (k = 0.2423 W/m∙K). The inside-wall temperature of the pipe is 811 K and the outside surface of the insulation is 310.8 K. For a 0.305 m length of pipe, calculate the heat loss and the temperature at the interface between the metal and the insulation.
1 answer:
Response:
Q=339.5W
T2=805.3K
Clarification:
Hello!
To tackle this issue, adhere to the following steps, and refer to the image for guidance.
1. Outline the problem thoroughly.
2. To determine heat, derive the heat transfer equation for cylinders transitioning from the interior of the metal tube to the exterior of the insulation.
3. After calculating the heat, establish the heat transfer equation for cylinders moving from the metal tube's inner section to its outer part, then solve for the temperature.
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Answer:
The power of the pump is 23.09 kW.
Explanation:
Parameters
gravitational constant,
mass flow rate,
flow density,
efficiency of the pump,
output gauge pressure,
input gauge pressure,
cross-sectional area of output pipe,
cross-sectional area of input pipe,
height of discharge, (evaluated at pump’s maximum height of 1.22 m)
input height,
hydraulic power of the pump,
Initially, the volumetric flow (Q) needs to be determined
Next, compute the velocity (v) for both input and output
Subsequently, the total head (H) can be calculated
Finally, the computation of pump power is done as follows