Answer: The number of sulfur dioxide molecules present is 1.27·10²³.
Calculating: m(SO₂) equals 13.5 g.
Using the formula n(SO₂) = m(SO₂) ÷ M(SO₂).
This gives n(SO₂) = 13.5 g ÷ 64 g/mol.
Resulting in n(SO₂) = 0.21 mol.
Subsequently, N(SO₂) = n(SO₂) ·Na.
Therefore, N(SO₂) = 0.21 mol · 6.022·10²³ 1/mol.
Ultimately, N(SO₂) equals 1.27·10²³.
Where n represents amount of substance.
M refers to molar mass.
Na is Avogadro's number.
Vegetation cover serves as the most efficient and effective method to curb sediment loss. The roots of plants like grass interlink soil particles, aiding in erosion resistance, particularly against runoff water. Vegetation absorbs the force of raindrops, preventing soil particle detachment. Additionally, plants can lie flat resembling shingles on a roof, enabling runoff to travel over the soil rather than disturbing it.
Tall, erect vegetation functions as a barrier against wind, diminishing its force so that it cannot dislodge soil particles from the ground surface.