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Misha Larkins
27 days ago
12

You are asked to go into the lab and prepare an acetic acid - sodium acetate buffer solution with a ph of 4.00  0.02. what mola

r ratio of ch3cooh to ch3coona should be used?
Chemistry
1 answer:
castortr0y [2.7K]27 days ago
5 0
Greetings!

To tackle this question, we will apply the Henderson-Hasselbach equation and solve for the molar ratio. It’s essential to obtain the pKa value for Acetic Acid, which is listed in reference tables as 4.76:

 pH=pKa + log ( \frac{[CH_3COONa]}{[CH_3COOH]} )

\frac{[CH_3COOH]}{[CH_3COONa}= 10^{(pH-pKa)^{-1}}=10^{(4-4,76)^{-1}}=5,75

Thus, the mole ratio of CH₃COOH to CH₃COONa is 5.75

Wishing you a wonderful day!

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\log (\frac{K_2}{2.57M^{-1}s^{-1}})=\frac{1.5\times 10^5J/mol}{2.303\times 8.314J/mole.K}[\frac{1}{701K}-\frac{1}{525K}]

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