Answer:
(1) En to n-1 = 0.55 eV
(2) En-1 to n-2 = 0.389 eV
(3) ninit =4
(4) L =483.676 ×10^-11 nm
(5) λlongest= 1773.33 nm
Explanation:
The comprehensive details regarding the answer are provided in the attached files.
Simone is walking her dog on a leash. The dog is pulling with a force of 32 N to the right and Simone is pulling backward with a
2 answers:
Conclusion:
The total net force acting on the objects is 16 N, directed towards the right.
Clarification:
It is stated that,
The force exerted by the dog, (to the right)
The force exerted by Simone, (backward)
Here, assume the backward direction is negative and the right direction is positive.
The net force will move in the direction where the larger force is present. The net force can be calculated as:
F = 16 N
Thus, the net force amounts to 16 N, acting towards the right.
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Answer:
The BMX rider lands 5.4 meters horizontally away from the ramp's end.
Explanation:
The BMX position vector is represented as:
r = (x0 + v0 × t × cos α, y0 + v0 × t × sin α + ½ × g × t²)
Where:
r = position at time t
x0 = initial horizontal position
v0 = initial speed
α = angle of jump
y0 = initial vertical height
g = gravitational acceleration (-9.8 m/s², upward positive)
Refer to the diagram for clarity. At the landing time, the vertical coordinate of the position vector is -2.4 m, measured from the ramp's edge as the origin. Using the vertical component equation for y, one can solve for t, then substitute t to find the horizontal distance.
The vertical position equation:
-2.4 m = 0 + 5.9 m/s × t × sin 40° - ½ × 9.8 m/s² × t²
Rearranged:
0 = -4.9 t² + 5.9 t × sin 40° + 2.4
Solving this quadratic yields:
t = 1.2 seconds
Then, calculate horizontal distance:
x = 0 + 5.9 m/s × 1.2 s × cos 40° = 5.4 m
This means the BMX lands 5.4 meters from the ramp's edge.
Have a great day!
Response:
The horizontal span of Sosa is 276.526 ft or 84.28 meters.
Explanation:
As illustrated in the diagram, let point O denote Sosa's starting position. She travels 361 ft at a 50-degree angle relative to the horizontal.
sin 50 =
0.7660 = h / 361
h = 276.526 ft
h = 84.28 meters
The horizontal distance of Sosa is 276.526 ft or 84.28 meters.
