To find the time required for one revolution, compute as follows:
0.510 s / 440 revolutions = 51/44000 s
. The frequency in Hertz is the reciprocal of this figure, resulting in a frequency of about 862.75 Hz.
The angular velocity in radians per second
is calculated as (440 rev / 0.510 s) x (2π rad / 1 rev) = 5420.787 rad/s
. The period, which is the inverse of frequency, is approximately equal to 1.16x10^-3 s.
Answer:
As indicated in the attached document
Explanation:
The comprehensive steps, mathematical reasoning, and manipulations are presented in the attachment.
Answer:
The cooker receives an average energy transfer rate of 1.80 kW.
Explanation:
Given that,
Pressure of the boiling water = 300 kPa
Mass of water = 3 kg
Duration = 30 min
Dryness fraction of the water = 0.5
What is the average energy transfer rate to the cooker?
We know that,
The specific enthalpy of vapor at 300 kPa is


We need to determine the initial state enthalpy of water


We must find the enthalpy of water in the final state
Using the enthalpy formula

Insert the value into the formula


Next, we calculate the energy transfer rate to the cooker
Using the energy rate formula

Substituting the value into the formula


Therefore, the average energy transfer rate to the cooker stands at 1.80 kW.