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Fed
2 months ago
7

The tip of a tuning fork goes through 440 complete vibrations in a time of 0.510s. Find the angular frequency and the period of

the motion.
Physics
2 answers:
Ostrovityanka [3.2K]2 months ago
8 0
In 0.510 seconds, there are 44 complete vibrations. To find the duration of a single vibration, divide 0.510 by 44, resulting in approximately 0.01159 seconds. Therefore, the period T equals 0.01159 seconds. The frequency f is given by 1/T, which calculates to about 86.28 Hz. The angular frequency ω is calculated as 2πf, resulting in approximately 542.11 rad/s.
Yuliya22 [3.3K]2 months ago
7 0
To find the time required for one revolution, compute as follows:
0.510 s / 440 revolutions = 51/44000 s
. The frequency in Hertz is the reciprocal of this figure, resulting in a frequency of about 862.75 Hz.
The angular velocity in radians per second
is calculated as (440 rev / 0.510 s) x (2π rad / 1 rev) = 5420.787 rad/s
. The period, which is the inverse of frequency, is approximately equal to 1.16x10^-3 s.
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