Answer:
The partial pressure of SO₃ is measured at 82.0 atm.
Explanation:
The equilibrium constant Kp is defined as the ratio of the equilibrium pressures of the gaseous products, each raised to the power of their respective coefficients in the reaction, divided by the pressures of the gaseous reactants raised to their coefficients.
For the given reaction,
2 SO₂(g) + O₂(g) → 2 SO₃(g)
![Kp = 0.345 = \frac{(pSO_{3})^{2} }{(pSO_{2})^{2} \times pO_{2} }\\pSO_{3} = \sqrt[]{0.345 \times (pSO_{2})^{2} \times pO_{2} } \\pSO_{3} = \sqrt[]{0.345 \times (35.0)^{2} \times 15.9 } \\pSO_{3} = 82.0 atm](https://tex.z-dn.net/?f=Kp%20%3D%200.345%20%3D%20%5Cfrac%7B%28pSO_%7B3%7D%29%5E%7B2%7D%20%7D%7B%28pSO_%7B2%7D%29%5E%7B2%7D%20%5Ctimes%20pO_%7B2%7D%20%7D%5C%5CpSO_%7B3%7D%20%3D%20%5Csqrt%5B%5D%7B0.345%20%5Ctimes%20%28pSO_%7B2%7D%29%5E%7B2%7D%20%5Ctimes%20pO_%7B2%7D%20%7D%20%5C%5CpSO_%7B3%7D%20%3D%20%5Csqrt%5B%5D%7B0.345%20%5Ctimes%20%2835.0%29%5E%7B2%7D%20%5Ctimes%2015.9%20%7D%20%5C%5CpSO_%7B3%7D%20%3D%2082.0%20atm)
Answer:
1.5
Explanation:
It is given that:
Compound A and B originate from Sulfur + Oxygen.
Compound A:
6g sulfur + 5.99g Oxygen
Compound B:
8.6g sulfur + 12.88g oxygen
By comparing the ratios:
Compound A:
S: O = 6.00: 5.99
S/0 = 6.0g S / 5.99g O
Compound B:
S: O = 8.60: 12.88
S / O = 8.60g S / 12.88g O
The mass ratio of A and that of B
(6.0g S / 5.99g O) ÷ (8.60g S / 12.88g O)
(6.0 g S / 5.99g O) × (12.88g O / 8.60g S)
(6 × 12.88) / (5.99 × 8.60)
= 77.28 / 51.514
= 1.50017
= 1.5
To determine the length of each side,
employ the distance formula represented by the equation:
Distance = ((x2-x1)^2+(y2-y1)^2)^0.5
Calculating
<span>AB = 8 units BC = 6 units AC = 10 units
</span><span>MN =8units NO = 6 units MO = 10 units
</span><span>XY = 6.32 units YZ = 6.32 units XZ = 8.94 units
</span>JK = 4.47 units KL = 4.47 units JL = 6 units
1 The correct response is option b) triangles ABC and MNO are Congruent. <span>These triangles, ABC and MNO, have congruent side lengths.
</span>2 The answer is option c) rotation.
There is a rotation of 90º around the origin for triangles ABC and MNO, where B=N,
B=N
C----------O
A----------M
