If the standard solutions had unknowingly been made up to be 0.0024 m agno3 and 0.0040 m k2cro4, would this have affected your r

Question

natka813

2 months ago

6

If the standard solutions had unknowingly been made up to be 0.0024 m agno3 and 0.0040 m k2cro4, would this have affected your r

esults? how?

Chemistry

2 answers:

alisha [2.9K] · Answer 1 · 2026-03-14T03:06:58+03:00

alisha [2.9K]2 months ago

6 0

2AgNO3+K2CrO4⇒Ag2CrO4(s)+2KNO3
Consequently, by combining 0.0024M AgNO3 and 0.004M
K2CrO4, Ag2CrO4 will precipitate and we're left with
0.0024M KNO3, mixed with (0.004-0.0024/2)M, yielding possibly 0.0028M concentration of K2CrO4

lorasvet [2.7K] · Answer 2 · 2026-03-14T03:09:30+03:00

Had the standard solutions been unintentionally prepared to be 0.0024 M AgNO₃ and 0.0040 M K₂CrO₄, the resulting chemical equation would be:

2AgNO₃ + K₂CrO₄ → Ag₂CrO₄ (s) + 2KNO₃

When combining 0.0024 M AgNO₃ and 0.004 M K₂CrO₄, Ag₂CrO₄ would precipitate.

Consequently, the remaining solution would contain 0.0024 M KNO₃ along with (0.004 -0.0024 / 2) M = 0.0028 M of K₂CrO₄.