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natka813
25 days ago
6

If the standard solutions had unknowingly been made up to be 0.0024 m agno3 and 0.0040 m k2cro4, would this have affected your r

esults? how?
Chemistry
2 answers:
alisha [2.8K]25 days ago
6 0
2AgNO3+K2CrO4⇒Ag2CrO4(s)+2KNO3
Consequently, by combining 0.0024M AgNO3 and 0.004M
K2CrO4, Ag2CrO4 will precipitate and we're left with
0.0024M KNO3, mixed with (0.004-0.0024/2)M, yielding possibly 0.0028M concentration of K2CrO4
lorasvet [2.6K]25 days ago
6 0

Had the standard solutions been unintentionally prepared to be 0.0024 M AgNO₃ and 0.0040 M K₂CrO₄, the resulting chemical equation would be:  

2AgNO₃ + K₂CrO₄ → Ag₂CrO₄ (s) + 2KNO₃

When combining 0.0024 M AgNO₃ and 0.004 M K₂CrO₄, Ag₂CrO₄ would precipitate.  

Consequently, the remaining solution would contain 0.0024 M KNO₃ along with (0.004 -0.0024 / 2) M = 0.0028 M of K₂CrO₄.  

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<span> </span><span>1. Other (Alcohol)
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1 month ago
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Montrel takes a trip to Central America during the winter. He finds out that the temperature in Central America is about the sam
lorasvet [2668]

Answer:

C

Explanation

My teacher mentioned that, for instance, Florida tends to be warm, while Central America can have both hot and cold temperatures, and a jacket isn't necessary. I don't recall many details.

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A sample of neon gas at STP is allowed to expand into an evacuated vessel. What is the sign of work for this process?
Alekssandra [2891]

Answer:

The work done in this process will be considered Negative.

Explanation:

The energy transferred by the system to the environment is negative

Therefore, if work is done on the system, it is labeled as positive. Conversely, when work is done by the system, it is regarded as negative.

In this scenario, the argon gas is expanding, and the work is exerted by the system into the surroundings (container), making the sign Negative.

Thus, the result for the work pertaining to this process will carry a Negative sign.

3 0
1 month ago
A 0.652-g sample of a pure strontium halide reacts with excess sulfuric acid. the solid strontium sulfate formed is separated, d
lorasvet [2668]

Answer:

The original halide's formula is SrCl₂.

Explanation:

  • The chemistry reaction's balanced equation is:

SrX₂ + H₂SO₄ → SrSO₄ + 2 HX, where X indicates the halide.

  • Based on the equation's stoichiometry, 1.0 mole of strontium halide yields 1.0 mole of SrSO₄.
  • The moles of SrSO₄ (n = mass/molar mass) = (0.755 g) / (183.68 g/mole) = 4.11 x 10⁻³ mole.
  • The moles of SrX can thus be calculated as 4.11 x 10⁻³ moles based on stoichiometry from the balanced equation.
  • n = mass / molar mass, thus n =  4.11 x 10⁻³ moles and mass = 0.652 g.
  • The molar mass of SrX₂ is calculated using mass / n = (0.652) / (4.11 x 10⁻³ moles) = 158.62 g/mole.
  • The molar mass of SrX₂ (158.62 g/mole) = Atomic mass of Sr (87.62 g/mole) + (2 x Atomic mass of halide X).
  • Calculating the atomic mass of halide X, we find = (158.62 g/mole) - (87.62 g/mole) / 2 = 71 / 2  g/mole = 35.5 g/mole.
  • This identifies the atomic mass of Cl.
  • Consequently, the original halide's formula is SrCl₂.
4 0
1 month ago
If two solutions with concentrations of 0.4 M sugar and 0.7 M sugar respectively are separated by a semipermeable membrane, duri
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Response: Water molecules migrate from the dilute to the concentrated solution

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During osmosis, when a solution is separated by a semipermeable membrane, the solvent (commonly water) moves from the less concentrated solution, regarding solute content, through the semipermeable membrane towards the solution with a higher concentration to balance the concentration levels between the two solutions.

Thus, in this scenario, water molecules flow from the 0.4M sugar solution to the 0.7M sugar solution through the semipermeable membrane.

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18 days ago
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