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Drupady
24 days ago
8

Simon has collected three samples from the coral reef where he observes marine life. He must determine whether each one is a pur

e substance or a mixture.
A 4-column table with 3 rows. The first column has entries sample A, sample B, sample C. The second column labeled appearance has entries clear liquid, clear blue liquid, opaque whitish liquid. The third column labeled when heated has entries evaporates completely at 70 degrees C, boils at 90 degrees Cleaving blue crystals behind, boils at 100 degrees leaving white crystals behind. The fourth column labeled when left over time has entries appearance does not change, appearance does not change, dust appears to settle at the bottom.

Sample A is a
, Sample B is a
, and Sample C is a
.
Chemistry
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Identify the number of moles in 369 grams of calcium hydroxide. Use the periodic table and the polyatomic ion resource.
Alekssandra [3086]

Response: The moles in 369 grams of calcium hydroxide are 4.98 moles

Reasoning: Given,

Mass of calcium hydroxide = 369 g

Molar mass of calcium hydroxide = 74.093 g/mole

Formula used:

\text{Moles of calcium hydroxide}=\frac{\text{Mass of calcium hydroxide}}{\text{Molar mass of calcium hydroxide}}

Now substituting the provided values into this formula, you will find the moles of calcium hydroxide.

\text{Moles of calcium hydroxide}=\frac{369g}{74.093g/mole}=4.98mole

Thus, the number of moles in 369 grams of calcium hydroxide is, 4.98 moles

7 0
2 months ago
What is the mass in grams of KBr in 0.400 L of a 0.350 M solution???
Anarel [2989]
The mass of KBr required is 16.7 g. This concludes from a volume of 0.400 L and a concentration of 0.350 M. Utilizing the molarity formula, moles are calculated as 0.14, leading to a molecular weight calculation of 119 g/mol, thus resulting in a mass of 16.7 g of KBr.
8 0
2 months ago
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Milk, if 2.00 liters has a mass of 2.06 kg. Find the density in g/cm^3
lorasvet [2795]
The density is 1.03 g/cm³. Explanation: The density of a substance is calculated with the formula: 1 kg = 1000 g therefore 2.06 kg = 2060 g. 1 L = 1000 cm³ thus 2 L = 2000 cm³. We now find: Mass = 2060 g Volume = 2000 cm³. Thus, the final answer of density is: 1.03 g/cm³. I hope this information assists you.
5 0
2 months ago
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