Response: The moles in 369 grams of calcium hydroxide are 4.98 moles
Reasoning: Given,
Mass of calcium hydroxide = 369 g
Molar mass of calcium hydroxide = 74.093 g/mole
Formula used:

Now substituting the provided values into this formula, you will find the moles of calcium hydroxide.

Thus, the number of moles in 369 grams of calcium hydroxide is, 4.98 moles
The mass of KBr required is 16.7 g. This concludes from a volume of 0.400 L and a concentration of 0.350 M. Utilizing the molarity formula, moles are calculated as 0.14, leading to a molecular weight calculation of 119 g/mol, thus resulting in a mass of 16.7 g of KBr.
The density is 1.03 g/cm³.
Explanation: The density of a substance is calculated with the formula:
1 kg = 1000 g therefore 2.06 kg = 2060 g.
1 L = 1000 cm³ thus 2 L = 2000 cm³.
We now find:
Mass = 2060 g
Volume = 2000 cm³.
Thus, the final answer of density is:
1.03 g/cm³.
I hope this information assists you.