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2 days ago

Assume you are given an int variable named nElements and a 2-dimensional array that has been created and assigned to a2d. Write

one or more statements that assign to nElements the total number of elements that could be stored in the entire 2-dimensional array.

Physics

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At time t=0 a proton is a distance of 0.360 m from a very large insulating sheet of charge and is moving parallel to the sheet w

serg [3582]

Explanation:

The formula for the electric field produced by an infinite sheet of charge is outlined below.

E = $\frac{\sigma}{2 \epsilon_{o}}$

where, $\sigma$ is the surface charge density

Following this, the formula for the electric force acting on a proton is given as:

F = eE

where, e is the charge of a proton

According to Newton's second law of motion, the overall force on the proton can be expressed as follows.

F = ma

a = $\frac{eE}{m}$

= $\frac{e(\frac{\sigma}{2 \epsilon_{o}})}{m}$

= $\frac{e \sigma}{2m \epsilon_{o}}$

According to kinematic equations, the proton's speed in the perpendicular direction can be described as follows.

$v_{f} = v_{i} + at$

= $(0 m/s) + \frac{e \sigma}{2 m \epsilon_{o}}t$

= $\frac{1.6 \times 10^{-19}C \times 2.34 \times 10^{-9} C/m^{2} \times 5.40 \times 10^{-8}s}{2 \times (1.67 \times 10^{-27} kg)(8.85 \times 10^{-12} C^{2}/Nm^{2}}$

= 683.974 m/s

Thus, the overall speed of the proton can be calculated as follows.

v' = $\sqrt{(960 m/s)^{2} + (683.974 m/s)^{2}}$

= $\sqrt{921600 + 467820.43}$

= $\sqrt{1389420.43}$

= 1178.73 m/s

Consequently, we conclude that the proton's speed is 1178.73 m/s.

3 0

2 months ago

During a snowball fight two balls with masses of 0.4 and 0.6 kg, respectively, are thrown in such a manner that they meet head-o

Yuliya22 [3333]

Answer:

The snowball's speed after the impact is 3 m/s

Explanation:

Given the following:

mass of each ball

m₁ = 0.4 Kg

m₂ = 0.6 Kg

initial speed of both balls = v₁ = 15 m/s

Speed of 1 Kg mass post-collision =?

Applying conservation of momentum

m₁ v₁ - m₂ v₁ = (m₁+m₂) V

A negative velocity indicates that the second ball moves in the opposite direction.

0.4 x 15 - 0.6 x 15 = (1) V

Therefore,

V = - 3 m/s

Consequently,

The snowball's speed following the collision is 3 m/s

8 0

2 months ago

An advertiser who calls a basement apartment a “garden apartment” is using the rhetorical device called

serg [3582]

I would choose B or D, based on the location. If it’s situated in South Kensington, London, then D might be appropriate. Conversely, if it’s in an underprivileged area, I'd opt for B.

3 0

2 months ago

a 75 kg man is standing at rest on ice while holding a 4kg ball. if the man throws the ball at a velocity of 3.50 m/s forward, w

Keith_Richards [3271]

Answer:

The resulting velocity for him will be 0.187 m/s in reverse direction.

Explanation:

Given:

The mass of the man is, $M=75\ kg$