This problem can be solved using Ampere’s Law:
<span>Bh = μoNI </span>
In this equation:
B = Magnetic Field
h = length of the coil
<span>μo = permeability = 4π*10^-7 T·m/A</span>
N = number of coil turns
I = current
Given values are B = 0.0015T, I = 1.0A, h = 10 cm = 0.1m<span>
Utilizing Ampere's law to determine the number of turns:
This can be rearranged to:
<span>N = Bh/μoI</span>
N = (0.0015)(0.1)/(4π*10^-7)(1.0)
N = 119.4
</span>
<span>Final answer:
119.4 turns</span>
<span>The partial pressure of A = 1.06 atm and the partial pressure of B = 0.53 atm</span>
The mass of the baked loaf will be lower than that of the dough.
U = 1794.005 × 10⁶ J. Explanation: Information provided indicates that the capacitance of the original capacitor is C = 1.27 F, and the potential difference applied to it is V = 59.9 kV, or 59.9 × 10³ V. The potential energy (U) for the capacitor is determined by the formula: U = (1/2) × C × V². Substituting the respective values, we find U = (1/2) × 1.27 × (59.9 × 10³)², resulting in U = 1794.005 × 10⁶ J.
