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fgiga
1 month ago
6

Calculate the partial pressure of ozone at 441 ppb if the atmospheric pressure is 0.67 atm.

Physics
1 answer:
kicyunya [3.2K]1 month ago
5 0

Answer:

2.95\times 10^{-7}atm

Explanation:

It's provided that

Atmospheric pressure=0.67 atm

We need to determine the partial pressure of ozone at 441 ppb.

Partial pressure of ozone=\frac{441\times atmospheric\;pressure}{10^9} atm

Inserting the given atmospheric pressure

Thus, we find

Partial pressure of ozone=\frac{441\times 0.67}{10^9}=2.95\times 10^{-7} atm

Consequently, the partial pressure of ozone is=2.95\times 10^{-7}atm

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A new roller coaster contains a loop-the-loop in which the car and rider are completely upside down. If the radius of the loop i
Sav [3153]

Respuesta:

11.4 m/s

Explicación:

La fórmula para la aceleración centrípeta es:

a=\frac{v^2}{R}

donde, a es la aceleración, v la velocidad alrededor de la circunferencia y R el radio del círculo.

En este problema,

a = g = aceleración debida a la gravedad en la cima = 9.81\ m/s^2

v = ?

R = 13.2 m

Por lo tanto,

9.81=\frac{v^2}{13.2}

v^2=9.81\times {13.2}

v = 11.4 m/s

8 0
3 months ago
Alicia intends to swim to a point straight across a 100 m wide river with a current that flows at 1.2 m/s. She can swim 2.5 m/s
Sav [3153]

Answer:

θ = 61.3°

Alicia must swim at an angle of 61.3°

Explanation:

Parameters given include:

Width of the river = 100 m

Alicia's speed in still water = 2.5 m/s

Speed of river's current = 1.2 m/s

The angle she needs to swim can be determined by combining the velocities, taking into account the current's influence.

Her swimming speed aimed against the current must offset the current's velocity;

2.5cosθ - 1.2 = 0

2.5cosθ = 1.2

cosθ = 1.2/2.5

θ = cosinverse(1.2/2.5)

θ = 61.3°

4 0
2 months ago
Suppose that an owner of the same dog breed has also taken some measurements. They notice that the surface area of the dog has i
inna [3103]

Answer:

The surface area of the dog changes from A to 3A

Explanation:

It is stated that the dog's surface area has increased by a factor of 3 over four years.

We need to calculate the change in the relative surface area of the dog over this timeframe.

Let’s assume the initial surface area is A.

Since the surface area has been multiplied by 3,

it follows that the surface area after four years is equal to 3×A = 3A.

Thus, the dog's surface area transitions from A to 3A.

7 0
2 months ago
Suppose a new asteroid was recently discovered which takes 557 months to orbit the Sun once (that's equal to 16,700 days or 46.4
Keith_Richards [3271]

Answer:

The average distance of the new asteroid from the Sun is estimated to be (2.02 × 10⁶) km.

Explanation:

The orbital speed of planets varies based on their distance from the Sun, which also affects their orbital period.

With its 557 months, equivalent to 46.4 years for an orbit around the Sun, the new asteroid's speed is situated between the orbital speeds of Saturn and Uranus.

Uranus orbits the Sun in 84 years at 24.61 km/hour,

while Saturn completes its orbit in 29.4 years at 34.82 km/hour.

To interpolate the speed for our asteroid at 46.4 years,

we denote its speed as x.

84 years ----> 24.61 km/h

46.4 years ----> x km/h

29.4 years -----> 34.82 km/h

Setting up the proportion:

(84 - 46.4)/(46.4 - 29.4) = (24.61 - x)/(x - 34.82)

Solving for x gives the asteroid's speed as 31.64 km/hr.

To find the average speed, use the formula:

Average speed = (total distance)/(time taken).

The total distance covered equals the circumference of the orbit around the Sun = 2πR,

where R = distance from the asteroid to the Sun.

Time taken = 16700 days = 16700 × 24 hours = 400800 hours.

Thus, we find that 31.64 = (2πR)/400800.

From this, we get 2πR = 31.64 × 400800 = 12681312 km.

And, R = 12681312/(2π) = 2018293.5 km = (2.02 × 10⁶) km.

8 0
2 months ago
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