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10 hours ago

Two friends are carrying a crate of mass 200 kg up a flight of stairs. The crate has length 1.25 m and height 0.500 m, and its c

enter of gravity is at its center. The stairs make a 45? angle with respect to the floor. The crate also is carried at an angle 45?, so that its bottom side is parallel to the slope of the stairs. The force each person applies is vertical.A) What is the magnitude of the upper person's force?B) What is the magnitude of the force applied by the bottom person?C) Is it best to be the person above or below on the stairs?

Physics

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A window washer on a hanging platform cleans the outside of windows on a skyscraper. The washer hoists the platform up the side

kicyunya [3294]

Answer:

The acceleration of the platform is - 1.8 m/s²

Explanation:

The net force on a body causes that body to accelerate in the direction of the resultant force applied.

Setting up the force equilibrium for the configuration:

ma = 800 - mg

100a = 800 - 100×9.8

100a = - 180

a = - 1.8 m/s²

This indicates that the body is falling downward.

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3 months ago

Medical cyclotrons need efficient sources of protons to inject into their center. In one kind of ion source, hydrogen atoms (i.e

Keith_Richards [3271]

Answer:

The radius is $r = 4.434 *10^{-5} \ m$

Explanation:

The problem states that

The magnetic field is $B = 90 mT = 90*10^{-3} \ T$

The electron kinetic energy is $KE = 1.4 eV = 1.4 * (1.60*10^{-19}) =2.24*10^{-19} \ J$

In general, for a collision to happen, the centripetal force on the electron in its orbit must equal the magnetic force acting on it

This can be mathematically expressed as

$\frac{mv^2}{r} = qvB$

=> $r = \frac{m* v}{q * B}$

Where m denotes the electron’s mass, which has a value of $m = 9.1 *10^{-31} \ kg$

v signifies the escape velocity, mathematically represented as

$v = \sqrt{\frac{2 * KE}{m} }$

Thus,

$r = \frac{m}{qB} * \sqrt{\frac{2 * KE}{m} }$

applying indices

$r = \frac{\sqrt{2 * KE * m} }{qB}$

substituting these values

$r = \frac{\sqrt{2 * 2.24*10^{-19}* 9.1 *10^{-31}} }{ 1.60 *10^{-19}* 90*10^{-3}}$

$r = 4.434 *10^{-5} \ m$

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2 months ago

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ValentinkaMS [3465]

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3 months ago

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