Response:
Some thermal energy is wasted and some is utilized to perform work.
Clarification:
The first law of thermodynamics asserts that energy cannot be created or annihilated. This principle essentially denotes energy conservation.
In mathematical form, it's expressed as:
Where,
signifies the change in internal energy
Q represents the absorbed heat
W is the work accomplished
The second law indicates that in an isolated system, entropy will either rise or remain unchanged; it can never diminish.
The interrelation between the first and second laws is (2) " Some thermal energy is wasted and some is utilized to perform work ".
Answer:
The equivalent distance in kilometers is 4012 × km.
Explanation:
It's known that 1 millimeter converts to meters. Then, 1 meter converts to
kilometers. Therefore, the conversion for 1 millimeter to kilometers can be stated as
1 mm = m
1 m = km
Thus, 1 mm = ×
km =
km.
Given the distance of 4012 mm, the corresponding distance in kilometers will be
4012 mm = 4012 × km.
The distance therefore is 4012 × km.
Result: -50.005 kJ
Details:
Provided Data
mass of the system = 10 kg
work done = 0.147 kJ/kg
Elevation change
initial speed
Final Speed
Specific internal Energy
according to the first Law of thermodynamics
where KE represents kinetic energy
PE indicates potential energy
U denotes internal Energy
Q = 1.47 + 3.375 - 4.850 - 50
Q = -50.005 kJ
Answer:
a)
b)
c)
Explanation:
According to the problem, the distance from the building where the ball hits is 16m, and its final elevation exceeds the initial height by 8m.
With this information, we can compute the ball’s starting speed.
a) Let's first assess the horizontal trajectory.
(1)
This gives us our initial equation.
Next, we need to examine the vertical trajectory.
Utilizing in our first equation (1)
Now let’s solve for t.
The ball takes two seconds to reach the adjacent building, allowing us to compute its initial speed.
b) To determine the velocity magnitude just before impact, we must calculate both x and y components.
The computed velocity magnitude is:
c) The ball's angle is: