PLEASE ANSWER FAST!!!!

Answer:

The best mortgage option for them is (3).

Step-by-step explanation:

Mortgage offers (1) and (2) are similar since Damarco and Tanya's down payment of $34,000 (20% of the purchase price) requires them to pay interest over 30 years for both scenarios. Although option (1) entails approximately $750 monthly payments and option (2) requires about $9,000 annually, the total payments are quite comparable as option (2)'s interest rate, starting at 3.5%, could potentially rise but is unlikely to exceed 5%, while option (1) maintains a fixed annual interest rate of 4.25%.

Option (3), however, demands interest payments for only 8 years at a relatively lower annual rate of 4%. If they commit to $18,000 annually with a $34,000 down payment and repay the remaining balance (under $35,000) at the end of 8 years, it leads to the lowest total payment and quickest mortgage clearance among the three options. Therefore, this choice aligns best with their financial objectives.

The year 1915 marks a population of 15,689. In 1940, it increased to 39,381. The required time to reach this figure is t = 137.9 years. Step-by-step explanation: To answer, we apply an exponential growth formula: A = P (1 + r) t, where P is the original number of individuals, r is the growth rate in decimal, and t is the time in years. Plugging in provided values: A = 6,250 (1 + 0.0375)^t. For the year 1915, as 1915-1890 translates to 25 years: A = 6,250 (1.0375)^25 yields 15,689. For 1940, as 1940-1890 indicates 50 years passed: A = 6,250 (1.0375)^50 results in 39,381. To find when the population hits 1,000,000, substitute A=1,000,000 and solve for t. This leads to 1,000,000/6,250 = (1.0375)^t implying log(160) = t * log(1.0375) results in t being approximately 137.9 years.

Response:

(a) The linear depreciation function relating to the car's value y after a few years t is given by:

y = 25,425 - 2,739 × t

(b) The projected worth of the car in 7 years amounts to $6,252.

(c) The depreciation is at a rate of $2,739 yearly.

Step-by-step explanation:

The manufacturer's suggested retail price (MSRP) for the vehicle is $25,425.

Its expected valuation in 5 years is $11,730.

(a) The linear depreciation formula is as follows:

Where;

Asset Cost = $25,425

Salvage Value = $11,730

Asset Lifespan = 5 years

From this, we obtain;

Thus, the linear depreciation function can be expressed as:

y - 25,425 = -2,739×(t - 0)

y = -2,739·t + 0 + 25,425 = 25,425 -2,739·t

y = 25,425 - 2,739 × t

Where;

y = The estimated worth of the car after a specified duration

t = The years calculated for depreciation

(b) The value of the vehicle in 7 years can be calculated as below;

For t = 7, we find;

y = 25,425 -2,739·t = y = 25,425 -2,739 × 7 = $6,252

The expected car value after 7 years is $6,252.

(c)

The car depreciates at a yearly rate of $2,739.

Response:

Step-by-step breakdown:

2x²-13x+21+6x²+29x-5

=8x²+16x+16