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Oksana_A
1 month ago
8

Suppose Mitch Marner (mass=80kg) and Zdano Chara (mass=116kg) collide head-on at the blue line when Marner is skating 10m/s and

Chara is standing still. Whose velocity would change more and Why?
Physics
1 answer:
Maru [3.3K]1 month ago
5 0

Answer:

1) Marner experiences a greater change in velocity

2) This happens because Chara has a greater mass compared to Marner, leading to a smaller change in velocity for Chara

Explanation:

Here are the details:

Mitch Marner's mass = 80 kg

Zdano Chara’s mass = 116 kg

Marner's speed prior to the collision = 10 m/s

According to the conservation of momentum, the sum of momentum before the collision equals the sum of momentum afterward:

m₁×u₁ + m₂×u₂ = m₁×v₁ + m₂×v₂

Where;

m₁ = Mitch Marner's mass = 80 kg

m₂ = Zdano Chara's mass = 116 kg

u₁ = Mitch Marner's initial velocity = 10 m/s

u₂ = Zdano Chara's initial velocity = 0 m/s

v₁ = Mitch Marner's final velocity

v₂ = Zdano Chara's final velocity

Assuming a direct collision, both players will have an identical instantaneous velocity just after impact, thus;

v₁ = v₂ = v

The equation can be expressed as;

m₁×u₁ + m₂×u₂ = (m₁ + m₂) × v₂

Substituting the numbers gives;

80 × 10 + 116 × 0 = (80 + 116) × v = 196 × v

Which simplifies to;

80 × 10 + 116 × 0 = 196 × v

800 = 196 × v

Thus, v = 800/196 = 100/49 = 4\frac{4}{19} \ m/s

This means the final instantaneous velocity for both Marner and Chara is 4\frac{4}{19} \ m/s

The change in velocity for Marner = 10 - 4\frac{4}{19} = 5\frac{15}{19} \ m/s

The change in velocity for Chara = 4\frac{4}{19} - 0 = 4\frac{4}{19} \ m/s

Therefore;

1) Marner's velocity changes more significantly

2) The reason being her mass relative to the total mass of both is smaller than Chara's mass relative to their total mass

This indicates that Marner's velocity alteration exceeds that of Chara due to Marner's lower mass.

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