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Nadusha1986
1 hour ago
7

Gasoline is a mixture of hydrocarbons, a major component of which is octane, CH3CH2CH2CH2CH2CH2CH2CH3. Octane has a vapor pressu

re of 13.95 torr at 25∘C and a vapor pressure of 144.78 torr at 75∘C. Use these data and the equation in part (a) to calculate the heat of vaporization of octane.
Chemistry
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Bleach contains the active ingredient NaClO. Analysis of bleach involves two sequential redox reactions: First, bleach is reacte
VMariaS [2998]

Answer:

0.31%

Explanation:

For the chemical reaction:

I₂ + 2 S₂O₃²⁻ → 2 I⁻ + S₄O₆²⁻

0.043 L multiplied by 0.117 M of sodium thiosulfate gives 5.031x10⁻³ moles of S₂O₃²⁻

5.031x10⁻³ moles of S₂O₃²⁻ produces:

ClO⁻⁻ + 2 H⁺ + 2 I⁻ → I₂ + Cl⁻ + H2O

2.5156x10⁻³ moles of I₂ equates to moles of NaClO

2.5156x10⁻³ moles of NaClO times \frac{74,44 g}{1mol} yields 0.187 g of NaClO

Thus, the mass percentage composition is:

\frac{0,187 g of NaClO}{60 g Of Bleach} x 100 = 0.31%

I hope this helps!

5 0
2 months ago
If 3.8 kcal is released by combustion of each gram of glucose, how many kilocalories are released by the combustion of 1.50 mol
castortr0y [3046]
684 kcal. One mole of glucose weighs roughly 180g. Given that 1g of glucose releases 3.8 kcal, we calculate for 1 mole of glucose: 180g -> 180g * 3.8 kcal/g = 684 kcal.
7 0
2 months ago
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