The force of the box’s weight acting perpendicular to the slope can be computed using the formula:
F = wcos(a)
In this equation, F represents the component of the weight perpendicular to the slope,
W denotes the box's total weight,
and A is the angle of the slope.
Thus, substituting values gives: F = (46)cos(25)
Resulting in F = 42 N
The soccer ball's initial speed stands at 16.38 m/s. Given that the vertical distance is y = 2.44 m, the horizontal span x = 10.0 m, and the angle of launch θ = 25.0°. The initial velocity comprises two components, Vₓ and V. The calculations are as follows: Vₓ = V cosθ and V = V sinθ. The formula for horizontal distance becomes x = Vₓt. Since g is deemed 0, we can state that: x = Vₓt or 10 = V cos 25 * t. Solving for V gives us 10 = 0.906V * t, thus V * t = 10 / 0.906 = 11.038 m. Regarding the vertical distance (with g being negative due to the upward movement opposing gravity), we use y = V sinθ * t - 1/2 * g * t². Following through with the calculations leads us to determine that the soccer ball's initial speed is indeed 16.38 m/s.
The approximate answer is 6.84. Reasoning: (2.78^2 + 6.25^2)^(1/2) = 6.84 approx.
U = 0, the initial vertical velocity
Ignoring air resistance, with g set to 9.8 m/s².
The duration, t, required for the pen to reach a vertical speed of 19.62 m/s can be calculated with
19.62 m/s = 0 + (9.8 m/s²)*(t s)
t = 19.62/9.8 = 2.00 s
Result: 2.0 s
