Answer: 339.148N
Explanation:
Given data:
Time (t) = 47s
Initial speed (U) = 0m/s
Final speed (V) = 9.5m/s
Mass of B = 540kg
Frictional force on B = 230N
Since both boats are linked, movement of A causes B to move as well.
What is the acceleration of boat A?
Applying the motion formula:
V = u + at
9.5 = 0 + a * 47
a = 9.5 / 47
a = 0.2021 m/s²
To determine the force necessary to accelerate boat B, as both boats experience the same force:
F = Mass * acceleration
F = 540 * 0.2021 = 109.14N
Given that there is a frictional force of 230N acting on boat B, the overall force (Tension) becomes:
Tension = frictional force + applied force = (109.14 + 230)N = 339.148N
Answer:
d) v1 = v2 = v3
Explanation:
This can be determined through the principle of energy conservation. We assess the total mechanical energy E=K+U (the sum of kinetic energy and gravitational potential energy) at both the initial and final positions, ensuring they remain constant.
<pInitially, for the three spheres, we have:
Finally, for the three spheres, we see:
<pGiven that
, and since
remains identical for all spheres, it follows that
is identical for all spheres, indicating that
, the final velocity, is equal for each ball.
According to Snell’s Law:
Where: is the index of refraction of the first medium (glass), and is the index of refraction of the second medium (ice). The angle of incidence and the angle of refraction are represented by and. The refractive index quantifies the speed of light in a medium. The critical angle is identified as the angle at which total internal reflection occurs, meaning no light passes through into another medium. This phenomenon happens only when the light is transitioning from a medium with a higher index of refraction to one with a lower index of refraction.
Let's consider a few possibilities.
1. The lowest velocity of the paratrooper would be just before hitting the ground.
2. Given that the jump originated from a relatively short height, the paratrooper utilized a static line, allowing the parachute to deploy almost instantly after leaping.
Hence, we will convert 100 mi/h to ft/s:
100 mi/h * 5280 ft/mi / 3600 s/h = 146.67 ft/sec.
Based on the first assumption, the maximum distance fallen by the paratrooper would equate to 8 seconds at 146.67 ft/s, translating to
8 s * 146.67 ft/s = 1173.36 ft.
This calculated distance is nearly on par with the jump height, validating both assumptions 1 and 2. Thus, this scenario seems plausible.
Moreover, considering the terminal velocity for a parachutist in a freefall position with limbs spread out typically reaches 120 mi/h, which is slightly above the 100 mi/h mentioned in the article. This as well aligns with the notion of the parachute acting like a flag, adding some air resistance.
Explanation:
Here’s a revised version of the requirements;
Fill in the blanks with the appropriate terms. Picture a force gauge fixed between the rope and the saddle of the chain carousel. If you keep your feet off the ground while the vehicle is not in motion, the dynamometer shows A / B. When the carousel is spinning, you’ll see C / D displayed on the dynamometer.
A. Your weight including the saddle
C. Value of the rope's strength
B. Your weight
D. Value of the centripetal force
