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Olegator
17 days ago
9

Which of the following conditions will ensure that a chemical reaction will definitely proceed in the forward direction, toward

products?a. ΔH>0b. ΔS>ΔH/Tc. ΔSsys>0d. ΔSsurr>ΔSsyse. ΔH<0
Chemistry
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Identify the number of moles in 369 grams of calcium hydroxide. Use the periodic table and the polyatomic ion resource.
Alekssandra [3086]

Response: The moles in 369 grams of calcium hydroxide are 4.98 moles

Reasoning: Given,

Mass of calcium hydroxide = 369 g

Molar mass of calcium hydroxide = 74.093 g/mole

Formula used:

\text{Moles of calcium hydroxide}=\frac{\text{Mass of calcium hydroxide}}{\text{Molar mass of calcium hydroxide}}

Now substituting the provided values into this formula, you will find the moles of calcium hydroxide.

\text{Moles of calcium hydroxide}=\frac{369g}{74.093g/mole}=4.98mole

Thus, the number of moles in 369 grams of calcium hydroxide is, 4.98 moles

7 0
2 months ago
In a chemical reaction that takes place at a fixed pressure and volume, the enthalpy change (ΔH) is –585 kJ/mol. Will this react
VMariaS [2998]

According to the sign convention, a negative ΔH indicates that the reaction is exothermic, resulting in a loss of heat and a reduction in temperature.

5 0
3 months ago
Read 2 more answers
A 0.680 M Ca(OH)2 solution was prepared by dissolving 55.0 grams of Ca(OH)2 in enough water. What is the total volume of the sol
castortr0y [3046]
Convert 55.0g Ca(OH)2 to moles.

The calculation shows that 55.0g of Ca(OH)2 corresponds to 0.742 moles.

To find the volume, divide 0.742 mol of Ca(OH)2 by its molarity of 0.680M, yielding approximately 1.09L of Ca(OH)2.

If you disregard the negligible volume of the Ca(OH)2 itself, the resulting total volume of a 0.680M solution created by dissolving 55.0g of Ca(OH)2 in an appropriate amount of water would be 1.09L.
4 0
3 months ago
Read 2 more answers
Determine the number of bonding electrons and the number of nonbonding electrons in the structure of xef2. enter the number of b
KiRa [2933]

Result: The count of bonding electrons and non-bonding electrons amounts to (4, 18).

Explanation:

The Lewis-dot structure reveals the number of bonding and non-bonding electrons in XeF_2.

Lewis-dot representation: It illustrates the valence electron count for atoms in a molecule and shows how they bond, as well as any lone pairs of electrons.

In this structure, 'Xe' is the central atom while 'F' is the terminal atom.

Xenon comprises 8 valence electrons, whereas fluorine contains 7.

The total number of valence electrons in XeF_2 is calculated as 8 + 2(7) = 22 electrons

From the Lewis-dot structure, we can determine

The count of electrons involved in bonding = 4

The count of electrons involved in non-bonding (lone-pairs) = 22 - 4 = 18

Thus, the bonding and non-bonding electron counts are (4, 18).

Below is the Lewis-dot structure for XeF_2.

4 0
2 months ago
Read 2 more answers
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