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spin
16 days ago
10

The average density of a planet is 3.05 g/cm3. What is its density in kg/m3? (Enter your answer in scientific notation.)

Chemistry
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Find the molarity of 750 ml solution containing 346 g of potassium nitrate
lorasvet [2795]
For KNO₃, the mass is 346g. The molar mass can be computed as (39.098) + (14) + (15.99*3), which results in 101.068 gmol⁻¹. The volume of the solution is given as 750ml, equivalent to 0.75dm³. The formula for molarity is (mass of solute/molar mass of solute)*(1/volume of solution in dm³). Accordingly, molarity = (346/101.068)*(1/0.75), yielding 4.56 mol dm⁻³.
5 0
2 months ago
Milk, if 2.00 liters has a mass of 2.06 kg. Find the density in g/cm^3
lorasvet [2795]
The density is 1.03 g/cm³. Explanation: The density of a substance is calculated with the formula: 1 kg = 1000 g therefore 2.06 kg = 2060 g. 1 L = 1000 cm³ thus 2 L = 2000 cm³. We now find: Mass = 2060 g Volume = 2000 cm³. Thus, the final answer of density is: 1.03 g/cm³. I hope this information assists you.
5 0
2 months ago
Read 2 more answers
Would an alkali metal make a good replacement for tin in a tin can? Explain.
Tems11 [2777]

Answer:

No

Explanation:

When heated, tin could react with alkali metals, releasing hydrogen gas.

6 0
2 months ago
What is the theoretical yield of ammonia, in kilograms, that we can synthesize from 5.22 kg of h2 and 31.5 kg of n2?
lions [2927]

The calculated theoretical yield of ammonia is 29.58 Kg

In the solution provided,

the mass of H_2 is 5.22 Kg, which equals 5220 g

the mass of N_2is 31.5 Kg, equivalent to 31500 g

The molar mass of H_2 is 2 g/mole

The molar mass of N_2 is 28 g/mole

The molar mass of NH_3 is 17 g/mole

First, we must calculate the moles of H_2 and N_2.

Moles of H_2= \frac{\text{ given mass of }H_2}{\text{ molar mass of }H_2}= \frac{5220g}{2g/mole}=2610moles

Moles of N_2 = \frac{\text{ given mass of }N_2}{\text{ molar mass of }N_2}= \frac{31500g}{28g/mole}=1125moles

Next, we need to find which reagent is limiting and which is excess.

The balanced equation for the reaction will be,

N_2+3H_2\rightarrow 2NH_3

Based on the balanced equation, we find that

1 mole of N_2 reacts with 3 moles of H_2

1125 moles of N_2 react with 3\times 1125=3375 moles of H_2

This indicates that H_2 is the limiting reagent and N_2 is in excess.

Now, we proceed to calculate the moles of ammonia.

According to the reaction, we determine that,

3 moles of H_2 will yield 2 moles of ammonia

2610 moles of H_2 will provide \frac{2}{3}\times 2610=1740 moles of ammonia

Finally, we will calculate the mass of the ammonia produced.

\text{Mass of }NH_3=\text{Moles of }NH_3\times \text{Molar mass of }NH_3

\text{Mass of }NH_3=(1740moles)\times (17g/mole)=29580g=\frac{29580}{1000}=29.58KgTherefore, the theoretical yield of ammonia is 29.58 Kg

8 0
3 months ago
Read 2 more answers
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