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Mandarinka
11 days ago
6

You are running a lemonade stand with your friend. You prepared 10 liters of 0.7 molarity lemonade, but your friend did online r

esearch and found that people prefer 0.4 Molarity lemonade. How can you fix the lemonade you made so that it is 0.4 Molarity without starting over?
Chemistry
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For H3PO4, Ka1 = 7.3 x 10^-3, Ka2 = 6.2 x 10^-6, and Ka3 = 4.8 x 10^-13. A 0.10 M aqueous solution of Na3PO4 therefore would be
Anarel [2989]
The aqueous solution of Na3PO4 is described as "strongly basic."
3 0
3 months ago
You have a racemic mixture of d-2-butanol and l-2-butanol. the d isomer rotates polarized light by +13.5∘. what is the rotation
Anarel [2989]
The L- isomer serves as the enantiomer of the D- isomer, and given that the optical rotation of the D- isomer is + 13.5°, the L- isomer's optical rotation will have the same magnitude but an opposite sign, resulting in -13.5°.

Thus, the rotation of the racemic mixture will be equal to 0°.


- This occurs because a racemic mixture contains equal proportions of both enantiomers.
8 0
3 months ago
A 0.89% (w/v) sodium chloride solution is referred to as physiological saline solution because it has the same concentration of
Tems11 [2777]
1) To express 0.89% m/v, it equals 0.89 grams of NaCl per 100 ml of solution.

This corresponds to 8.9 grams of NaCl in 1000 ml of solution, or 8.9 grams in 1 liter.

2) Molarity is represented as M = moles of solute / liters of solution.

Thus, we need to determine the moles in 8.9 grams of NaCl.

3) The molar mass of NaCl is calculated as 23.0 g/mol + 35.5 g/mol = 58.5 g/mol.

4) Therefore, the number of moles of NaCl calculates as mass / molar mass = 8.9 g / 58.5 g/mol = 0.152 moles.

5) Consequently, M = 0.152 moles of NaCl / 1 liter of solution = 0.152 M.

Answer: 0.152 M
4 0
3 months ago
If 1.0 mole of CH4 and 2.0 moles of Cl2 are used in the reaction CH4 + 4Cl2 => CCl4 + 4HCl then which of these statements is
lions [2927]

Answer:

B,C,D

Explanation:

The quantity of CCl4 produced is contingent on the amount of CH4 used in a 1:1 ratio. Given that there are twice as many moles of Cl2 compared to CH4, some Cl2 will remain unreacted. To fully utilize all Cl2, additional CH4 must be introduced into the reaction.

4 0
2 months ago
A 126-gram sample of titanium metal is heated from 20.0°C to 45.4°C while absorbing 1.68 kJ of heat. What is the specific heat o
lorasvet [2795]
The specific heat of titanium metal is 0.524 J/g°C. Given that Q = 1.68 kJ, which equates to 1680 Joules, with a mass of 126 grams and initial and final temperatures of 20°C and 45.4°C respectively, the specific heat is computed using the formula Q = (mass)(ΔT)(Cp), where ΔT = T₂ - T₁ = 25.4°C. Plugging in the numbers leads us to Cp = 0.524 J/g°C.
3 0
3 months ago
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