Gravitational potential energy is often released by burning substances. true or false

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Softa [3030]

Answer:

$H = 10.05 m$

Explanation:

The stone reaches the top of the flagpole at both t = 0.5 s and t = 4.1 s

therefore, the total duration of the upwards motion above the peak of the pole is provided as

$\Delta t = 4.1 - 0.5 = 3.6 s$

now we have

$\Delta t = \frac{2v}{g}$

$3.6 = \frac{2v}{9.8}$

$v = 17.64 m/s$

this indicates the speed at the flagpole's top

at this point we have

$v_f - v_i = at$

$17.64 - v_i = (-9.8)(0.5)$

$v_i = 22.5 m/s$

the height of the flagpole is stated as

$H = \frac{v_f + v_i}{2}t$

$H = \frac{22.5 + 17.64}{2} (0.5)$

$H = 10.05 m$

5 0

4 months ago

Softa [3030]

Answer:

I do not communicate in Spanish

Explanation:

4 0

3 months ago

Softa [3030]

Upon calculating, I'm nearly certain that the answer is "...to a height of 1.4 meters." Happy to assist!:)

4 0

3 months ago